To determine the probability that a person with an iron deficiency is 20 years or older, follow these steps:
1. Identify the total number of people with iron deficiency: From the provided table, we can see there are 102 people with iron deficiency in total.
2. Determine the number of people with iron deficiency aged 20 or older:
- Number of people with iron deficiency aged 20-30 years: 37
- Number of people with iron deficiency aged above 30 years: 24
Adding these two numbers gives the total number of people with iron deficiency who are 20 years or older:
[tex]\[
37 + 24 = 61
\][/tex]
3. Calculate the probability:
- The probability that a person with iron deficiency is 20 years or older is given by the ratio of the number of people with iron deficiency who are 20 years or older to the total number of people with iron deficiency.
[tex]\[
\text{Probability} = \frac{\text{Number of people with iron deficiency aged 20 or older}}{\text{Total number of people with iron deficiency}}
\][/tex]
Substituting the values, we get:
[tex]\[
\text{Probability} = \frac{61}{102}
\][/tex]
4. Simplify the fraction (if required and possible) and convert to a decimal.
[tex]\[
\text{Probability} = 0.5980392156862745
\][/tex]
Therefore, the probability that a person with an iron deficiency is 20 years or older is approximately 0.60. Hence, the correct answer is:
c. 0.60
