Answer :
Sure! Let's match the given neutralization reactions with the correct salts.
1. [tex]\( H_2SO_4 + 2 NH_4OH \rightarrow \)[/tex] ?
Neutralization reactions involve an acid and a base to produce water and a salt. In this reaction, [tex]\( H_2SO_4 \)[/tex] (sulfuric acid) reacts with [tex]\( NH_4OH \)[/tex] (ammonium hydroxide).
Products:
- The acid [tex]\( H_2SO_4 \)[/tex] provides [tex]\( SO_4^{2-} \)[/tex] ions.
- The base [tex]\( NH_4OH \)[/tex] provides [tex]\( NH_4^+ \)[/tex] ions.
Thus, the salt formed is [tex]\( (NH_4)_2SO_4 \)[/tex] (ammonium sulfate).
[tex]\[ H_2SO_4 + 2 NH_4OH \rightarrow (NH_4)_2SO_4 + 2 H_2O \][/tex]
[tex]\(\square\)[/tex] matches with [tex]\( (NH_4)_2SO_4 \)[/tex].
2. [tex]\( 2 NaOH + H_2CO_3 \rightarrow \)[/tex] ?
In this reaction, [tex]\( NaOH \)[/tex] (sodium hydroxide) reacts with [tex]\( H_2CO_3 \)[/tex] (carbonic acid).
Products:
- The acid [tex]\( H_2CO_3 \)[/tex] provides [tex]\( CO_3^{2-} \)[/tex] ions.
- The base [tex]\( NaOH \)[/tex] provides [tex]\( Na^+ \)[/tex] ions.
Thus, the salt formed is [tex]\( Na_2CO_3 \)[/tex] (sodium carbonate).
[tex]\[ 2 NaOH + H_2CO_3 \rightarrow Na_2CO_3 + 2 H_2O \][/tex]
[tex]\(\square\)[/tex] matches with [tex]\( Na_2CO_3 \)[/tex].
3. [tex]\( HNO_3 + KOH \rightarrow \)[/tex] ?
In this reaction, [tex]\( HNO_3 \)[/tex] (nitric acid) reacts with [tex]\( KOH \)[/tex] (potassium hydroxide).
Products:
- The acid [tex]\( HNO_3 \)[/tex] provides [tex]\( NO_3^- \)[/tex] ions.
- The base [tex]\( KOH \)[/tex] provides [tex]\( K^+ \)[/tex] ions.
Thus, the salt formed is [tex]\( KNO_3 \)[/tex] (potassium nitrate).
[tex]\[ HNO_3 + KOH \rightarrow KNO_3 + H_2O \][/tex]
[tex]\(\square\)[/tex] matches with [tex]\( KNO_3 \)[/tex].
Putting it all together:
1. [tex]\( H_2SO_4 + 2 NH_4OH \rightarrow (NH_4)_2SO_4 \)[/tex]
- Reaction 3: [tex]\( (NH_4)_2SO_4 \)[/tex]
2. [tex]\( 2 NaOH + H_2CO_3 \rightarrow Na_2CO_3 \)[/tex]
- Reaction 1: [tex]\( Na_2CO_3 \)[/tex]
3. [tex]\( HNO_3 + KOH \rightarrow KNO_3 \)[/tex]
- Reaction 2: [tex]\( KNO_3 \)[/tex]
Hence, the correct matches are:
1. Reaction 1: [tex]\( Na_2CO_3 \)[/tex]
2. Reaction 2: [tex]\( KNO_3 \)[/tex]
3. Reaction 3: [tex]\( (NH_4)_2SO_4 \)[/tex]
1. [tex]\( H_2SO_4 + 2 NH_4OH \rightarrow \)[/tex] ?
Neutralization reactions involve an acid and a base to produce water and a salt. In this reaction, [tex]\( H_2SO_4 \)[/tex] (sulfuric acid) reacts with [tex]\( NH_4OH \)[/tex] (ammonium hydroxide).
Products:
- The acid [tex]\( H_2SO_4 \)[/tex] provides [tex]\( SO_4^{2-} \)[/tex] ions.
- The base [tex]\( NH_4OH \)[/tex] provides [tex]\( NH_4^+ \)[/tex] ions.
Thus, the salt formed is [tex]\( (NH_4)_2SO_4 \)[/tex] (ammonium sulfate).
[tex]\[ H_2SO_4 + 2 NH_4OH \rightarrow (NH_4)_2SO_4 + 2 H_2O \][/tex]
[tex]\(\square\)[/tex] matches with [tex]\( (NH_4)_2SO_4 \)[/tex].
2. [tex]\( 2 NaOH + H_2CO_3 \rightarrow \)[/tex] ?
In this reaction, [tex]\( NaOH \)[/tex] (sodium hydroxide) reacts with [tex]\( H_2CO_3 \)[/tex] (carbonic acid).
Products:
- The acid [tex]\( H_2CO_3 \)[/tex] provides [tex]\( CO_3^{2-} \)[/tex] ions.
- The base [tex]\( NaOH \)[/tex] provides [tex]\( Na^+ \)[/tex] ions.
Thus, the salt formed is [tex]\( Na_2CO_3 \)[/tex] (sodium carbonate).
[tex]\[ 2 NaOH + H_2CO_3 \rightarrow Na_2CO_3 + 2 H_2O \][/tex]
[tex]\(\square\)[/tex] matches with [tex]\( Na_2CO_3 \)[/tex].
3. [tex]\( HNO_3 + KOH \rightarrow \)[/tex] ?
In this reaction, [tex]\( HNO_3 \)[/tex] (nitric acid) reacts with [tex]\( KOH \)[/tex] (potassium hydroxide).
Products:
- The acid [tex]\( HNO_3 \)[/tex] provides [tex]\( NO_3^- \)[/tex] ions.
- The base [tex]\( KOH \)[/tex] provides [tex]\( K^+ \)[/tex] ions.
Thus, the salt formed is [tex]\( KNO_3 \)[/tex] (potassium nitrate).
[tex]\[ HNO_3 + KOH \rightarrow KNO_3 + H_2O \][/tex]
[tex]\(\square\)[/tex] matches with [tex]\( KNO_3 \)[/tex].
Putting it all together:
1. [tex]\( H_2SO_4 + 2 NH_4OH \rightarrow (NH_4)_2SO_4 \)[/tex]
- Reaction 3: [tex]\( (NH_4)_2SO_4 \)[/tex]
2. [tex]\( 2 NaOH + H_2CO_3 \rightarrow Na_2CO_3 \)[/tex]
- Reaction 1: [tex]\( Na_2CO_3 \)[/tex]
3. [tex]\( HNO_3 + KOH \rightarrow KNO_3 \)[/tex]
- Reaction 2: [tex]\( KNO_3 \)[/tex]
Hence, the correct matches are:
1. Reaction 1: [tex]\( Na_2CO_3 \)[/tex]
2. Reaction 2: [tex]\( KNO_3 \)[/tex]
3. Reaction 3: [tex]\( (NH_4)_2SO_4 \)[/tex]