Alright, let's go through each neutralization reaction one by one and determine the salt formed.
### 1. [tex]\( H_2SO_4 + 2 NH_4OH \rightarrow \)[/tex] ?
This is a reaction between sulfuric acid ([tex]\(H_2SO_4\)[/tex]) and ammonium hydroxide ([tex]\(NH_4OH\)[/tex]).
Balanced equation:
[tex]\[ H_2SO_4 + 2 NH_4OH \rightarrow (NH_4)_2SO_4 + 2 H_2O \][/tex]
So, the salt formed is [tex]\((NH_4)_2SO_4\)[/tex] (ammonium sulfate).
Result:
[tex]\[ (NH_4)_2SO_4 \][/tex]
### 2. [tex]\( 2 NaOH + H_2CO_3 \rightarrow \)[/tex] ?
This is a reaction between sodium hydroxide ([tex]\(NaOH\)[/tex]) and carbonic acid ([tex]\(H_2CO_3\)[/tex]).
Balanced equation:
[tex]\[ 2 NaOH + H_2CO_3 \rightarrow Na_2CO_3 + 2 H_2O \][/tex]
So, the salt formed is [tex]\(Na_2CO_3\)[/tex] (sodium carbonate).
Result:
[tex]\[ Na_2CO_3 \][/tex]
### 3. [tex]\( HNO_3 + KOH \rightarrow \)[/tex] ?
This is a reaction between nitric acid ([tex]\(HNO_3\)[/tex]) and potassium hydroxide ([tex]\(KOH\)[/tex]).
Balanced equation:
[tex]\[ HNO_3 + KOH \rightarrow KNO_3 + H_2O \][/tex]
So, the salt formed is [tex]\(KNO_3\)[/tex] (potassium nitrate).
Result:
[tex]\[ KNO_3 \][/tex]
### Summary of reactions and the salts formed:
1. [tex]\( H_2SO_4 + 2 NH_4OH \rightarrow (NH_4)_2SO_4 + 2 H_2O \)[/tex]
2. [tex]\( 2 NaOH + H_2CO_3 \rightarrow Na_2CO_3 + 2 H_2O \)[/tex]
3. [tex]\( HNO_3 + KOH \rightarrow KNO_3 + H_2O \)[/tex]
Thus, the salts formed in each reaction are:
1. [tex]\((NH_4)_2SO_4\)[/tex] (ammonium sulfate)
2. [tex]\(Na_2CO_3\)[/tex] (sodium carbonate)
3. [tex]\(KNO_3\)[/tex] (potassium nitrate)
