Frosty0110
Answered

Match the salt with the acid and base used to form it in a neutralizing reaction.

A. [tex] K_2SO_4 [/tex]
1. KOH and [tex] H_2SO_4 [/tex]

B. NaBr
1. NaOH and HBr

C. [tex] H_3PO_4 [/tex] and NaOH
1. NaOH and HBr

D. [tex] HPO_4 [/tex] and KOH
1. KOH and [tex] H_2SO_4 [/tex]

E. NaCl and [tex] HSO_4 [/tex]
1. NaOH and HBr



Answer :

GinnyAnswer
Certainly! Let's go through matching the salts with their respective acids and bases used to form them in a neutralization reaction.

1. [tex]\( K_2SO_4 \)[/tex] (Potassium Sulfate)
- To form potassium sulfate ([tex]\( K_2SO_4 \)[/tex]), you need a strong base and a strong acid.
- The correct acid-base pair here is: KOH (Potassium Hydroxide) and [tex]\( H_2SO_4 \)[/tex] (Sulfuric Acid)
- Neutralization reaction:
[tex]\[ 2 KOH + H_2SO_4 \rightarrow K_2SO_4 + 2 H_2O \][/tex]

2. NaBr (Sodium Bromide)
- To form sodium bromide ([tex]\( NaBr \)[/tex]), the necessary sodium base and bromide acid are:
- The correct acid-base pair here is: NaOH (Sodium Hydroxide) and HBr (Hydrobromic Acid)
- Neutralization reaction:
[tex]\[ NaOH + HBr \rightarrow NaBr + H_2O \][/tex]

So, the correct matches are:

1. Potassium Sulfate ([tex]\( K_2SO_4 \)[/tex]) is formed by:
- KOH and [tex]\( H_2SO_4 \)[/tex]

2. Sodium Bromide (NaBr) is formed by:
- NaOH and HBr