Match the salt with the acid and base used to form it in a neutralizing reaction.

A. [tex] K_2SO_4 [/tex]
1. KOH and [tex] H_2SO_4 [/tex]

B. NaBr
1. NaOH and HBr

C. [tex] H_3PO_4 [/tex] and NaOH
1. NaOH and HBr

D. [tex] HPO_4 [/tex] and KOH
1. KOH and [tex] H_2SO_4 [/tex]

E. NaCl and [tex] HSO_4 [/tex]
1. NaOH and HBr

Question

22-07-2024
Chemistry

Answered

Match the salt with the acid and base used to form it in a neutralizing reaction.

A. [tex] K_2SO_4 [/tex]
1. KOH and [tex] H_2SO_4 [/tex]

B. NaBr
1. NaOH and HBr

C. [tex] H_3PO_4 [/tex] and NaOH
1. NaOH and HBr

D. [tex] HPO_4 [/tex] and KOH
1. KOH and [tex] H_2SO_4 [/tex]

E. NaCl and [tex] HSO_4 [/tex]
1. NaOH and HBr

Answer :

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GinnyAnswer GinnyAnswer · Answer 1 · 2024-07-22T04:59:20-04:00

Certainly! Let's go through matching the salts with their respective acids and bases used to form them in a neutralization reaction.

1. [tex]$ K_2SO_4 $[/tex] (Potassium Sulfate)
- To form potassium sulfate ([tex]$ K_2SO_4 $[/tex]), you need a strong base and a strong acid.
- The correct acid-base pair here is: KOH (Potassium Hydroxide) and [tex]$ H_2SO_4 $[/tex] (Sulfuric Acid)
- Neutralization reaction:
[tex]\[ 2 KOH + H_2SO_4 \rightarrow K_2SO_4 + 2 H_2O \][/tex]

2. NaBr (Sodium Bromide)
- To form sodium bromide ([tex]$ NaBr $[/tex]), the necessary sodium base and bromide acid are:
- The correct acid-base pair here is: NaOH (Sodium Hydroxide) and HBr (Hydrobromic Acid)
- Neutralization reaction:
[tex]\[ NaOH + HBr \rightarrow NaBr + H_2O \][/tex]

So, the correct matches are:

1. Potassium Sulfate ([tex]$ K_2SO_4 $[/tex]) is formed by:
- KOH and [tex]$ H_2SO_4 $[/tex]

2. Sodium Bromide (NaBr) is formed by:
- NaOH and HBr