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Identify the spectator ions in this reaction:

[tex]\[ H^{+} + Br^{-} + K^{+} + OH^{-} \rightarrow K^{+} + Br^{-} + H_2O \][/tex]

A. [tex]\( H^{+} \)[/tex] and [tex]\( K^{+} \)[/tex]

B. [tex]\( Br^{-} \)[/tex] and [tex]\( OH^{-} \)[/tex]

C. [tex]\( K^{+} \)[/tex] and [tex]\( Br^{-} \)[/tex]



Answer :

GinnyAnswer
To identify the spectator ions in the given chemical reaction:

[tex]\[ \text{H}^+ + \text{Br}^- + \text{K}^+ + \text{OH}^- \rightarrow \text{K}^+ + \text{Br}^- + \text{H}_2\text{O} \][/tex]

we need to determine which ions do not participate in the actual chemical change and remain unchanged on both sides of the reaction. Spectator ions are ions that exist as both reactants and products in the same form.

Let’s break down and examine the reaction step-by-step:

1. Identify reactants on the left side:
- [tex]\(\text{H}^+\)[/tex]
- [tex]\(\text{Br}^-\)[/tex]
- [tex]\(\text{K}^+\)[/tex]
- [tex]\(\text{OH}^-\)[/tex]

2. Identify products on the right side:
- [tex]\(\text{K}^+\)[/tex]
- [tex]\(\text{Br}^-\)[/tex]
- [tex]\(\text{H}_2\text{O}\)[/tex]

3. Compare ions on both sides:
- [tex]\(\text{K}^+\)[/tex] appears on both sides.
- [tex]\(\text{Br}^-\)[/tex] appears on both sides.
- [tex]\(\text{H}^+\)[/tex] (from the left) reacts with [tex]\(\text{OH}^-\)[/tex] (from the left) to form [tex]\(\text{H}_2\text{O}\)[/tex] on the right side; therefore, they are not spectator ions as they are involved in the formation of water.

Given that [tex]\(\text{K}^+\)[/tex] and [tex]\(\text{Br}^-\)[/tex] appear unchanged on both sides of the chemical equation, they are the spectator ions.

Thus, the spectator ions in this reaction are:

[tex]\[ \text{K}^+ \text{ and } \text{Br}^- \][/tex]

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