Determine the thrust needed to propulsively land the booster described below.
A 25000kg booster is falling. It experiences a gravitational pull of 245000N.The booster's engine fires for 13 seconds before landing, slowing the booster from a velocity of 172m/s downwards to 0m/s over that time.

According to Newton's second law of motion, the net force (∑F) on an object is equal to its mass (m) times its acceleration (a). The acceleration is equal to the change in velocity (Δv) over change in time (Δt). Drawing a free-body diagram, there are two forces on the booster: weight force mg pulling down, and thrust force T pushing up.

[tex]\Large \text {$ \Sigma F=ma $}\\\Large \text {$ T-mg=m $}\huge \text {$ \frac{\Delta v}{\Delta t} $}\\\Large \text {$ T-245,000\ N=(25,000\ kg) $}\huge \text {$ \frac{(0\ m/s-(-172\ m/s))}{13\ s} $}\\\Large \text {$ T\approx 576,000\ N $}[/tex]

Determine the thrust needed to propulsively land the booster described below. A 25000kg booster is falling. It experiences a gravitational pull of 245000N.The booster's engine fires for 13 seconds before landing, slowing the booster from a velocity of 172m/s downwards to 0m/s over that time.

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Determine the thrust needed to propulsively land the booster described below.
A 25000kg booster is falling. It experiences a gravitational pull of 245000N.The booster's engine fires for 13 seconds before landing, slowing the booster from a velocity of 172m/s downwards to 0m/s over that time.