b) On the occasion of Pratik's birthday, Pratik ate [tex]\(\frac{3}{10}\)[/tex] parts of a cake, his mother ate [tex]\(\frac{1}{4}\)[/tex] parts, his father ate [tex]\(\frac{1}{5}\)[/tex] parts, and he gave the remaining parts to his brother Bishwant.

(i) What parts of the cake did Pratik give to Bishwant?
(ii) Who ate the greatest parts of the cake?



Answer :

Of course! Let's break down the problem step-by-step:

### Part (i) What parts of the cake did Pratik give to Bishwant?

1. Determine the total fraction of the cake eaten by Pratik, his mother, and his father:

- Pratik ate [tex]\(\frac{3}{10}\)[/tex] of the cake.
- Pratik's mother ate [tex]\(\frac{1}{4}\)[/tex] of the cake.
- Pratik's father ate [tex]\(\frac{1}{5}\)[/tex] of the cake.

To combine these fractions, we need to find a common denominator. The denominators are 10, 4, and 5. The least common multiple (LCM) of 10, 4, and 5 is 20.

2. Convert each fraction to have the common denominator of 20:

- [tex]\(\frac{3}{10} = \frac{3 \times 2}{10 \times 2} = \frac{6}{20}\)[/tex]
- [tex]\(\frac{1}{4} = \frac{1 \times 5}{4 \times 5} = \frac{5}{20}\)[/tex]
- [tex]\(\frac{1}{5} = \frac{1 \times 4}{5 \times 4} = \frac{4}{20}\)[/tex]

3. Sum the fractions to find the total amount of cake eaten:

- Total eaten = [tex]\(\frac{6}{20} + \frac{5}{20} + \frac{4}{20} = \frac{15}{20}\)[/tex]

4. Calculate the parts of the cake given to Bishwant:

- The entire cake is [tex]\(1\)[/tex], so the parts given to Bishwant is [tex]\(1 - \frac{15}{20}\)[/tex].

To simplify this:

- [tex]\(\frac{15}{20} = 0.75\)[/tex]
- Parts given to Bishwant = [tex]\(1 - 0.75 = 0.25\)[/tex].

Therefore, Pratik gave Bishwant [tex]\(\frac{1}{4}\)[/tex] or [tex]\(0.25\)[/tex] parts of the cake.

### Part (ii) Who ate the greatest parts of the cake?

1. Compare the parts of the cake eaten by Pratik, his mother, and his father:

- Pratik: [tex]\(\frac{3}{10}\)[/tex] or [tex]\(0.30\)[/tex]
- Mother: [tex]\(\frac{1}{4}\)[/tex] or [tex]\(0.25\)[/tex]
- Father: [tex]\(\frac{1}{5}\)[/tex] or [tex]\(0.20\)[/tex]

2. Determine the greatest part:

- Pratik's [tex]\(0.30\)[/tex] is greater than Mother's [tex]\(0.25\)[/tex] and Father's [tex]\(0.20\)[/tex].

Therefore, Pratik ate the greatest parts of the cake, which is [tex]\(\frac{3}{10}\)[/tex] or [tex]\(0.30\)[/tex].

### Summary:

(i) Pratik gave Bishwant [tex]\(\frac{1}{4}\)[/tex] or [tex]\(0.25\)[/tex] parts of the cake.
(ii) Pratik ate the greatest parts of the cake, [tex]\(\frac{3}{10}\)[/tex] or [tex]\(0.30\)[/tex].