A clothing store kept track of types and sizes of clothing sold over the period of one week. The two-way table is given below.

\begin{tabular}{|l|c|c|c|c|}
\hline & Small & Medium & Large & Total \\
\hline T-Shirt & 11 & 15 & 8 & 34 \\
\hline Sweatshirt & 6 & 11 & 18 & 35 \\
\hline Sweatpants & 10 & 14 & 7 & 31 \\
\hline \multicolumn{1}{|c|}{ Total } & 27 & 40 & 33 & 100 \\
\hline
\end{tabular}

What is the probability that a randomly selected clothing item from this table is medium, given it is a sweatshirt?

[tex]\[
P(\text{Medium} \mid \text{Sweatshirt}) = [?]\%
\][/tex]

Round your answer to the nearest whole percent.



Answer :

Let's determine the probability that a randomly selected clothing item is medium, given that it is a sweatshirt. The given data from the table is as follows:

- Total number of sweatshirts: 35
- Number of sweatshirts that are medium: 11

We need to find the conditional probability [tex]\( P(\text{Medium} \mid \text{Sweatshirt}) \)[/tex], which is the probability that an item is medium-sized given that it is a sweatshirt. The formula for conditional probability is:

[tex]\[ P(\text{Medium} \mid \text{Sweatshirt}) = \frac{\text{Number of Medium Sweatshirts}}{\text{Total Number of Sweatshirts}} \][/tex]

Substitute the values:

[tex]\[ P(\text{Medium} \mid \text{Sweatshirt}) = \frac{11}{35} \][/tex]

Next, we convert this probability to a percentage by multiplying by 100:

[tex]\[ P(\text{Medium} \mid \text{Sweatshirt}) \times 100 = \left( \frac{11}{35} \right) \times 100 \approx 31.42857142857143 \][/tex]

Rounding to the nearest whole number:

[tex]\[ \approx 31\% \][/tex]

Therefore, the probability that a randomly selected clothing item is medium, given that it is a sweatshirt, is:

[tex]\[ P(\text{Medium} \mid \text{Sweatshirt}) = 31\% \][/tex]