A professional basketball player typically attempts 8 free throws per game. Let [tex]$X$[/tex] represent the number of free throws made out of 8. The distribution for [tex]$X$[/tex] is shown in the table.

\begin{tabular}{|c|c|c|c|c|c|c|c|c|c|}
\hline
Number of Free Throws Made & 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\
\hline
Probability & 0.002 & 0.008 & 0.04 & 0.12 & 0.23 & 0.28 & 0.21 & 0.09 & 0.02 \\
\hline
\end{tabular}

What is the median of the distribution?

A. 4
B. 4.5
C. 4.8
D. 5



Answer :

To find the median of a probability distribution, we need to determine the value at which the cumulative distribution reaches or exceeds 0.5. Here is a step-by-step solution:

1. Identify the given probabilities:
- The table provides the probabilities for the number of free throws made, ranging from 0 to 8.

[tex]$\begin{array}{|c|c|c|c|c|c|c|c|c|c|} \hline \text{Number of Free} & 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\ \text{Throws Made} & & & & & & & & & \\ \hline \text{Probability} & 0.002 & 0.008 & 0.04 & 0.12 & 0.23 & 0.28 & 0.21 & 0.09 & 0.02 \\ \hline \end{array}$[/tex]

2. Calculate the cumulative probabilities:
- Cumulative probability is the sum of the probabilities up to and including each value.

[tex]$\begin{array}{|c|c|c|c|c|c|c|c|c|c|} \hline \text{Number of Free} & 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\ \text{Throws Made} & & & & & & & & & \\ \hline \text{Cumulative Probability} & 0.002 & 0.01 & 0.05 & 0.17 & 0.4 & 0.68 & 0.89 & 0.98 & 1.0 \\ \hline \end{array}$[/tex]

3. Locate the median:
- The median is found where the cumulative probability first reaches or exceeds 0.5.
- From the cumulative probabilities above:

- For 0: 0.002
- For 1: 0.01
- For 2: 0.05
- For 3: 0.17
- For 4: 0.4
- For 5: 0.68 (this is the first value that exceeds 0.5)
- For 6: 0.89
- For 7: 0.98
- For 8: 1.0

The cumulative probability exceeds 0.5 at a value of 5 free throws.

Therefore, the median of the distribution for the number of free throws made is [tex]\( \boxed{5} \)[/tex].