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Two fruit flies that are heterozygous for body color and eye color are crossed. Brown body color is dominant to black body color. Red eye color is dominant to brown eye color.

Determine the genotypes of offspring 1-8.

1. [tex]$\square$[/tex]
2. [tex]$\square$[/tex]
3. [tex]$\square$[/tex]
4. [tex]$\square$[/tex]
5. [tex]$\square$[/tex]
6. [tex]$\square$[/tex]
7. [tex]$\square$[/tex]
8. [tex]$\square$[/tex]

\begin{tabular}{|c|c|c|c|}
\hline
& BE & Be & bE & be \\
\hline
BE & BBEE & BBEe & BbEE & BbEe \\
\hline
Be & BBEe & BBee & BbEe & Bbee \\
\hline
bE & BbEE & BbEe & bbEE & bbEe \\
\hline
be & BbEe & Bbee & bbEe & bbee \\
\hline
\end{tabular}



Answer :

GinnyAnswer
Sure, let's work through the problem step by step.

We have two fruit flies that are heterozygous for both body color and eye color. The genotype for both parents in terms of both traits is BbEe.

Here's how we construct the Punnett square for their offspring:

[tex]\[ \begin{array}{|c|c|c|c|c|} \hline & BE & Be & bE & be \\ \hline BE & BBEE & BBEe & BbEE & BbEe \\ \hline Be & BBEe & BBee & BbEe & Bbee \\ \hline bE & BbEE & BbEe & bbEE & bbEe \\ \hline be & BbEe & Bbee & bbEe & bbee \\ \hline \end{array} \][/tex]

Next, we assign the genotypes of the offspring in the required format.

1. The genotype for offspring 1 is 'BBEE' from the cross of BE (parent 1) and BE (parent 2).
2. The genotype for offspring 2 is 'BBEe' from the cross of BE (parent 1) and Be (parent 2).
3. The genotype for offspring 3 is 'BbEE' from the cross of BE (parent 1) and bE (parent 2).
4. The genotype for offspring 4 is 'BBee' from the cross of Be (parent 1) and Be (parent 2).
5. The genotype for offspring 5 is 'BbEe' from the cross of Be (parent 1) and bE (parent 2).
6. The genotype for offspring 6 is 'Bbee' from the cross of Be (parent 1) and be (parent 2).
7. The genotype for offspring 7 is 'bbEe' from the cross of bE (parent 1) and be (parent 2).
8. The genotype for offspring 8 is 'bbee' from the cross of be (parent 1) and be (parent 2).

Putting these genotypes into the requested format:

1. BBEE
2. BBEe
3. BbEE
4. BBee
5. BbEe
6. Bbee
7. bbEe
8. bbee

Therefore, the genotypes of offspring 1-8 are:

1. BBEE
2. BBEe
3. BbEE
4. BBee
5. BbEe
6. Bbee
7. bbEe
8. bbee

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