Answered

A part of an mRNA molecule with the following sequence is being read by a ribosome: [tex]5^{\prime}-\text{CCG-ACG}-3^{\prime}[/tex] (mRNA). The charged transfer RNA molecules shown in the figure below (with their anticodons shown in the [tex]3^{\prime} \text{ to } 5^{\prime}[/tex] direction) are available. Two of them can correctly match the mRNA so that a dipeptide can form:

\begin{tabular}{|c|c|}
\hline
tRNA Anticodon & Amino Acid \\
\hline
GGC & Proline \\
\hline
CGU & Alanine \\
\hline
UGC & Threonine \\
\hline
CCG & Glycine \\
\hline
ACG & Cysteine \\
\hline
CGG & Alanine \\
\hline
\end{tabular}

Which of the following dipeptides will be formed?



Answer :

To determine the dipeptides that will be formed from the given mRNA sequence and the available tRNA anticodons, we need to follow these steps:

1. Identify the mRNA codons: The given mRNA sequence is [tex]\(5' \text{CCG ACG} 3'\)[/tex]. We split this sequence into two codons:
[tex]\[ \begin{aligned} &\text{Codon 1: CCG} \\ &\text{Codon 2: ACG} \end{aligned} \][/tex]

2. Pair each mRNA codon with the appropriate tRNA anticodon: To find the tRNA anticodon that pairs with each mRNA codon, we need to apply the complementary base-pairing rules (A pairs with U, C pairs with G, G pairs with C, and U pairs with A). Note that tRNA anticodons are conventionally written in the [tex]\(3' \rightarrow 5'\)[/tex] direction.

- For mRNA codon [tex]\( \text{CCG} \)[/tex]:
[tex]\[ \text{Anticodon: GGC (3' to 5')} \][/tex]
This anticodon corresponds to the amino acid Proline.

- For mRNA codon [tex]\( \text{ACG} \)[/tex]:
[tex]\[ \text{Anticodon: UGC (3' to 5')} \][/tex]
This anticodon corresponds to the amino acid Threonine.

3. Determine the amino acids: Based on the pairing, we obtain:
- Codon [tex]\( \text{CCG} \)[/tex] pairs with tRNA anticodon [tex]\( \text{GGC} \)[/tex], attaching Proline.
- Codon [tex]\( \text{ACG} \)[/tex] pairs with tRNA anticodon [tex]\( \text{UGC} \)[/tex], attaching Threonine.

4. Form the dipeptide: Combining the amino acids from each codon results in the formation of the dipeptide:
[tex]\[ \text{Proline} - \text{Threonine} \][/tex]

Therefore, the dipeptide that will be formed from the given mRNA sequence and tRNA molecules is Proline-Threonine.