Solve the system of equations.

[tex]\[
\begin{array}{l}
x = 2y - 5 \\
-3x = -6y + 15
\end{array}
\][/tex]

A. [tex]\((1, -3)\)[/tex]

B. [tex]\((-2, -9)\)[/tex]

C. No solution

D. Infinite solutions



Answer :

Certainly! Let's solve the system of equations step by step.

We are given the following system of equations:

1. [tex]\( x = 2y - 5 \)[/tex]
2. [tex]\( -3x = -6y + 15 \)[/tex]

First, let's simplify the second equation:

[tex]\[ -3x = -6y + 15 \][/tex]

We can divide every term by -3 to make it simpler to work with:

[tex]\[ x = 2y - 5 \][/tex]

Now we observe that both equations simplify to:

[tex]\[ x = 2y - 5 \][/tex]

In this situation, we recognize that the above two equations are essentially identical. Since both equations represent the same line, every point [tex]\((x, y)\)[/tex] that satisfies one equation also satisfies the other.

This situation leads us to the following conclusions:

- Both equations are dependent on each other, meaning they describe the same line.
- Therefore, there are infinitely many solutions available, consisting of all points that lie on the line [tex]\( x = 2y - 5 \)[/tex].

Thus, the correct answer to the system of equations is:

d. Infinite solutions.