The line [tex]$y = x$[/tex] is transformed into the line [tex]$y = \frac{2x}{3} + 1$[/tex]. Fill in the blanks to describe the slope and [tex]y[/tex]-intercept of the new line.

The slope is [ [tex]\(\frac{2}{3}\)[/tex] ],
and the line is shifted [ up by 1 ].

The line is [ flatter ].



Answer :

To describe the transformation of the line [tex]\( y = x \)[/tex] into the line [tex]\( y = \frac{2x}{3} + 1 \)[/tex], let's fill in the blanks for the slope and compare it to the original line.

1. Slope: The slope of the original line [tex]\( y = x \)[/tex] is [tex]\( 1 \)[/tex]. For the new line [tex]\( y = \frac{2x}{3} + 1 \)[/tex], the slope is the coefficient of [tex]\( x \)[/tex], which is [tex]\( \frac{2}{3} \)[/tex].

So, the slope is [tex]\( \frac{2}{3} \)[/tex].

2. Shift in Steepness: To determine how the slope of the new line compares to the slope of the original line, we observe the values:
- The original slope is [tex]\( 1 \)[/tex].
- The new slope is [tex]\( \frac{2}{3} \)[/tex].

Since [tex]\( \frac{2}{3} \)[/tex] is less than [tex]\( 1 \)[/tex], the new line is less steep than the original line. Therefore, the new line is flatter.

So, the new line is shifted flatter.

Thus:

- The slope is [tex]\( \frac{2}{3} \)[/tex],
- and the line is shifted flatter.