Which equation is the inverse of [tex]y = 9x^2 - 4[/tex]?

A. [tex]y = \frac{\pm \sqrt{x + 4}}{9}[/tex]
B. [tex]y = \pm \sqrt{\frac{x}{9} + 4}[/tex]
C. [tex]y = \frac{\pm \sqrt{x + 4}}{3}[/tex]
D. [tex]y = \frac{\pm \sqrt{x}}{3} + \frac{2}{3}[/tex]



Answer :

To find the inverse of the function [tex]\( y = 9x^2 - 4 \)[/tex], we need to follow a series of steps to isolate [tex]\( x \)[/tex] and then solve for [tex]\( y \)[/tex]. Here’s the step-by-step process:

1. Start with the given function:

[tex]\[ y = 9x^2 - 4 \][/tex]

2. To find the inverse, we first swap [tex]\( y \)[/tex] and [tex]\( x \)[/tex]:

[tex]\[ x = 9y^2 - 4 \][/tex]

3. Solve for [tex]\( y \)[/tex]. Begin by isolating the term containing [tex]\( y \)[/tex]:

[tex]\[ x + 4 = 9y^2 \][/tex]

4. Next, divide both sides of the equation by 9:

[tex]\[ \frac{x + 4}{9} = y^2 \][/tex]

5. To solve for [tex]\( y \)[/tex], take the square root of both sides. Remember to consider the positive and negative square roots:

[tex]\[ y = \pm \sqrt{\frac{x + 4}{9}} \][/tex]

6. Simplify the expression under the square root:

[tex]\[ y = \pm \sqrt{\frac{x + 4}{9}} = \pm \frac{\sqrt{x + 4}}{3} \][/tex]

Therefore, the inverse function is:

[tex]\[ y = \frac{ \pm \sqrt{x+4}}{3} \][/tex]

Comparing this with the given options:

1. [tex]\( y = \frac{\pm \sqrt{x+4}}{9} \)[/tex]
2. [tex]\( y = \pm \sqrt{\frac{x}{9}+4} \)[/tex]
3. [tex]\( y = \frac{\pm \sqrt{x+4}}{3} \)[/tex]
4. [tex]\( y = \frac{\pm \sqrt{x}}{3} + \frac{2}{3} \)[/tex]

The correct answer is:

[tex]\[ y = \frac{\pm \sqrt{x+4}}{3} \][/tex]

Hence, the equation that represents the inverse of [tex]\( y = 9x^2 - 4 \)[/tex] is:

[tex]\[ y = \frac{\pm \sqrt{x+4}}{3} \][/tex]