Let's go through the process of predicting the products of the given chemical reaction and ensuring that the equation is balanced.
The reaction involves hydrochloric acid (HCl) in aqueous solution and water (H₂O) in liquid form. We need to determine the products of this reaction and balance the equation, including the state symbols.
1. Identify the reactants:
- Hydrochloric acid: [tex]\( \text{HCl} \)[/tex] (aq)
- Water: [tex]\( \text{H}_2\text{O} \)[/tex] (l)
2. Predict the products:
- When HCl, a strong acid, dissolves in water, it dissociates into its ions.
- Hydrochloric acid (HCl) will donate a proton (H⁺) to water (H₂O), forming hydronium ion (H₃O⁺) and chloride ion (Cl⁻).
3. Write the products with their state symbols:
- Hydronium ion: [tex]\( \text{H}_3\text{O}^+ \)[/tex] (aq)
- Chloride ion: [tex]\( \text{Cl}^- \)[/tex] (aq)
4. Form the chemical equation:
- The complete and balanced chemical equation is:
[tex]\[
\text{HCl} \, (\text{aq}) + \text{H}_2\text{O} \, (\text{l}) \rightarrow \text{H}_3\text{O}^+ \, (\text{aq}) + \text{Cl}^- \, (\text{aq})
\][/tex]
To summarize, the products of the reaction are hydronium ion ([tex]\( \text{H}_3\text{O}^+ \)[/tex]), and chloride ion ([tex]\( \text{Cl}^- \)[/tex]), both in an aqueous state. The balanced chemical equation is:
[tex]\[
\text{HCl} \, (\text{aq}) + \text{H}_2\text{O} \, (\text{l}) \rightarrow \text{H}_3\text{O}^+ \, (\text{aq}) + \text{Cl}^- \, (\text{aq})
\][/tex]
