Answer :
Certainly! Let's analyze the polynomial function [tex]\( f(x) = x(x - 4)(x + 2)^4 \)[/tex] in two parts: finding the zeros and determining the end behavior.
### Finding the Zeros
To find the zeros of the function, we need to determine the values of [tex]\( x \)[/tex] that make [tex]\( f(x) = 0 \)[/tex].
Given the function:
[tex]\[ f(x) = x(x - 4)(x + 2)^4 \][/tex]
Set [tex]\( f(x) = 0 \)[/tex] and solve for [tex]\( x \)[/tex]:
[tex]\[ x(x - 4)(x + 2)^4 = 0 \][/tex]
This equation will be zero if any of the individual factors are zero. Thus, we set each factor equal to zero and solve for [tex]\( x \)[/tex]:
1. [tex]\( x = 0 \)[/tex]
2. [tex]\( x - 4 = 0 \implies x = 4 \)[/tex]
3. [tex]\( (x + 2)^4 = 0 \implies x + 2 = 0 \implies x = -2 \)[/tex]
Therefore, the zeros of the function are:
[tex]\[ x = 0, \quad x = 4, \quad x = -2 \][/tex]
### End Behavior
To determine the end behavior of [tex]\( f(x) \)[/tex], we need to examine the leading term of the polynomial when it is expanded fully. The degree of [tex]\( f(x) \)[/tex] and the leading coefficient dictate the end behavior.
First, let's identify the degrees of each factor in the polynomial:
1. [tex]\( x \)[/tex] is of degree 1.
2. [tex]\( (x - 4) \)[/tex] is of degree 1.
3. [tex]\( (x + 2)^4 \)[/tex] is of degree 4.
When we multiply these factors, the degree of the polynomial is:
[tex]\[ 1 + 1 + 4 = 6 \][/tex]
So [tex]\( f(x) \)[/tex] is a 6th-degree polynomial.
The leading term will be obtained by multiplying the highest-degree terms from each factor:
[tex]\[ x \cdot x \cdot (x)^4 = x^6 \][/tex]
The coefficient of this leading term depends on any constants from the original factors, but in this polynomial, there are no additional coefficients, so the leading term is merely:
[tex]\[ x^6 \][/tex]
However, when analyzing end behavior, we need to consider the coefficients and any transformations in the function. Expanding this might involve constants, but for simplicity in this explanation, we’re focusing on the dominant [tex]\( x \)[/tex] value.
Thus the leading term is of the form:
[tex]\[ -64x^6 \][/tex] (where a constant such as -64 might be determined from deeper expansion, correcting the coefficient's presence.)
Next, we interpret the end behavior:
- Since the leading coefficient (after determining specific expansion constants, but typically 1 here without adjustments) is positive, and the degree is 6 (an even positive degree), as [tex]\( x \to \infty \)[/tex] or [tex]\( x \to -\infty \)[/tex], the function [tex]\( f(x) \)[/tex] will go towards [tex]\( +\infty \)[/tex].
In summary, the analyzed behavior indicates overwhelming tendency similar to even-degree behaviors with potentially accurate detailed pragmatic checks via individual terms assessed via complete expansions if necessary:
- For sufficiently large positive or negative [tex]\( x \)[/tex], [tex]\( f(x) \to \pm \infty \)[/tex].
### Summary
- The zeros of the function are [tex]\( x = 0 \)[/tex], [tex]\( x = 4 \)[/tex], and [tex]\( x = -2 \)[/tex].
- The end behavior exhibits growing large positive values as [tex]\( x \)[/tex] moves towards [tex]\( \infty \)[/tex] or [tex]\( -\infty \)[/tex]:
- For [tex]\( x \to \pm\infty \)[/tex], [tex]\( f(x) \to +\infty \)[/tex].
### Finding the Zeros
To find the zeros of the function, we need to determine the values of [tex]\( x \)[/tex] that make [tex]\( f(x) = 0 \)[/tex].
Given the function:
[tex]\[ f(x) = x(x - 4)(x + 2)^4 \][/tex]
Set [tex]\( f(x) = 0 \)[/tex] and solve for [tex]\( x \)[/tex]:
[tex]\[ x(x - 4)(x + 2)^4 = 0 \][/tex]
This equation will be zero if any of the individual factors are zero. Thus, we set each factor equal to zero and solve for [tex]\( x \)[/tex]:
1. [tex]\( x = 0 \)[/tex]
2. [tex]\( x - 4 = 0 \implies x = 4 \)[/tex]
3. [tex]\( (x + 2)^4 = 0 \implies x + 2 = 0 \implies x = -2 \)[/tex]
Therefore, the zeros of the function are:
[tex]\[ x = 0, \quad x = 4, \quad x = -2 \][/tex]
### End Behavior
To determine the end behavior of [tex]\( f(x) \)[/tex], we need to examine the leading term of the polynomial when it is expanded fully. The degree of [tex]\( f(x) \)[/tex] and the leading coefficient dictate the end behavior.
First, let's identify the degrees of each factor in the polynomial:
1. [tex]\( x \)[/tex] is of degree 1.
2. [tex]\( (x - 4) \)[/tex] is of degree 1.
3. [tex]\( (x + 2)^4 \)[/tex] is of degree 4.
When we multiply these factors, the degree of the polynomial is:
[tex]\[ 1 + 1 + 4 = 6 \][/tex]
So [tex]\( f(x) \)[/tex] is a 6th-degree polynomial.
The leading term will be obtained by multiplying the highest-degree terms from each factor:
[tex]\[ x \cdot x \cdot (x)^4 = x^6 \][/tex]
The coefficient of this leading term depends on any constants from the original factors, but in this polynomial, there are no additional coefficients, so the leading term is merely:
[tex]\[ x^6 \][/tex]
However, when analyzing end behavior, we need to consider the coefficients and any transformations in the function. Expanding this might involve constants, but for simplicity in this explanation, we’re focusing on the dominant [tex]\( x \)[/tex] value.
Thus the leading term is of the form:
[tex]\[ -64x^6 \][/tex] (where a constant such as -64 might be determined from deeper expansion, correcting the coefficient's presence.)
Next, we interpret the end behavior:
- Since the leading coefficient (after determining specific expansion constants, but typically 1 here without adjustments) is positive, and the degree is 6 (an even positive degree), as [tex]\( x \to \infty \)[/tex] or [tex]\( x \to -\infty \)[/tex], the function [tex]\( f(x) \)[/tex] will go towards [tex]\( +\infty \)[/tex].
In summary, the analyzed behavior indicates overwhelming tendency similar to even-degree behaviors with potentially accurate detailed pragmatic checks via individual terms assessed via complete expansions if necessary:
- For sufficiently large positive or negative [tex]\( x \)[/tex], [tex]\( f(x) \to \pm \infty \)[/tex].
### Summary
- The zeros of the function are [tex]\( x = 0 \)[/tex], [tex]\( x = 4 \)[/tex], and [tex]\( x = -2 \)[/tex].
- The end behavior exhibits growing large positive values as [tex]\( x \)[/tex] moves towards [tex]\( \infty \)[/tex] or [tex]\( -\infty \)[/tex]:
- For [tex]\( x \to \pm\infty \)[/tex], [tex]\( f(x) \to +\infty \)[/tex].