A circuit has a voltage drop of [tex]24.0 \, V[/tex] across a [tex]30.0 \, \Omega[/tex] resistor that carries a current of [tex]0.800 \, A[/tex]. What is the power conducted by the resistor? Use [tex]P = V \cdot I[/tex].

A. 19.2 W
B. 720.0 W
C. 1.25 W
D. 24.0 W



Answer :

To determine the power conducted by the resistor, we can use the formula for electrical power based on voltage and current:

[tex]\[ P = V \times I \][/tex]

Where:
- [tex]\( P \)[/tex] is the power in watts (W)
- [tex]\( V \)[/tex] is the voltage in volts (V)
- [tex]\( I \)[/tex] is the current in amperes (A)

Given the problem:
- The voltage drop ([tex]\( V \)[/tex]) is 24.0 V
- The current ([tex]\( I \)[/tex]) is 0.800 A

Substitute the given values into the formula:

[tex]\[ P = 24.0 \, \text{V} \times 0.800 \, \text{A} \][/tex]

Now multiply the values:

[tex]\[ P = 24.0 \times 0.800 \][/tex]
[tex]\[ P = 19.2 \, \text{W} \][/tex]

So, the power conducted by the resistor is 19.2 watts. Therefore, the correct answer is:

A. 19.2 W