On a true-false quiz of six questions, Karen guesses at each answer.

What is the probability that she answers the first three questions correctly and the last three questions incorrectly?

A. [tex]\frac{1}{8}[/tex]
B. [tex]\frac{1}{32}[/tex]
C. [tex]\frac{1}{64}[/tex]
D. [tex]\frac{1}{4}[/tex]



Answer :

To determine the probability that Karen answers the first three questions correctly and the last three questions incorrectly on a true-false quiz of six questions, we can follow these steps:

1. Calculate the Probability of Answering a Single Question Correctly or Incorrectly:

Since the quiz is true-false, there are only two possible outcomes for each question – "true" or "false". Therefore, the probability of guessing any single question correctly is:
[tex]\[ p_\text{correct} = \frac{1}{2} \][/tex]
Similarly, the probability of guessing any single question incorrectly is:
[tex]\[ p_\text{incorrect} = \frac{1}{2} \][/tex]

2. Probability of Answering the First Three Questions Correctly:

The probability of answering the first question correctly is [tex]\( \frac{1}{2} \)[/tex]. Since each question is independent of the others, the probability that Karen guesses the first three questions correctly is the product of the individual probabilities:
[tex]\[ p_\text{first three correct} = \left(\frac{1}{2}\right) \times \left(\frac{1}{2}\right) \times \left(\frac{1}{2}\right) = \left(\frac{1}{2}\right)^3 = \frac{1}{8} \][/tex]

3. Probability of Answering the Last Three Questions Incorrectly:

Similarly, the probability of answering the last question incorrectly is [tex]\( \frac{1}{2} \)[/tex]. The probability that Karen guesses the last three questions incorrectly is:
[tex]\[ p_\text{last three incorrect} = \left(\frac{1}{2}\right) \times \left(\frac{1}{2}\right) \times \left(\frac{1}{2}\right) = \left(\frac{1}{2}\right)^3 = \frac{1}{8} \][/tex]

4. Total Probability of the Specified Event:

To find the total probability that Karen answers the first three questions correctly and the last three questions incorrectly, we multiply the probabilities of these two independent events:
[tex]\[ p_\text{total} = p_\text{first three correct} \times p_\text{last three incorrect} = \frac{1}{8} \times \frac{1}{8} = \frac{1}{64} \][/tex]

So, the probability that Karen answers the first three questions correctly and the last three questions incorrectly is:
[tex]\[ \boxed{\frac{1}{64}} \][/tex]