\begin{tabular}{|c|c|}
\hline Time (t) & Elevation (e) \\
\hline -2 & [tex]$a$[/tex] \\
\hline 3.5 & [tex]$b$[/tex] \\
\hline 30 & [tex]$c$[/tex] \\
\hline
\end{tabular}

Rory is staying in a cabin on a hill 300 feet above sea level. She walks down the hill to the water's edge. The equation of her average change in elevation over time is [tex]$e = 300 - 10t$[/tex], where [tex]$t$[/tex] is the time in minutes since she left the cabin, and [tex][tex]$e$[/tex][/tex] is her elevation with regard to sea level.

Which values are viable points, and what are their values in the table relating [tex]$t$[/tex] and [tex]$e$[/tex]?

\begin{array}{l}
a = \square \\
b = \square \\
c = \square
\end{array}



Answer :

Certainly! Let's solve the problem step-by-step given the equation [tex]\( e = 300 - 10t \)[/tex], where [tex]\( e \)[/tex] is the elevation in feet, and [tex]\( t \)[/tex] is the time in minutes.

### Time (t) = -2:
1. Substitute [tex]\( t = -2 \)[/tex] into the equation:
[tex]\[ e = 300 - 10(-2) \][/tex]
2. Simplify the equation:
[tex]\[ e = 300 + 20 = 320 \][/tex]
3. So, [tex]\( a = 320 \checkmark \)[/tex] (indicating it is a viable point since Rory could have been at this elevation before starting her descent).

### Time (t) = 3.5:
1. Substitute [tex]\( t = 3.5 \)[/tex] into the equation:
[tex]\[ e = 300 - 10(3.5) \][/tex]
2. Simplify the equation:
[tex]\[ e = 300 - 35 = 265.0 \][/tex]
3. So, [tex]\( b = 265.0 \checkmark \)[/tex] (indicating it is a viable point).

### Time (t) = 30:
1. Substitute [tex]\( t = 30 \)[/tex] into the equation:
[tex]\[ e = 300 - 10(30) \][/tex]
2. Simplify the equation:
[tex]\[ e = 300 - 300 = 0 \][/tex]
3. So, [tex]\( c = 0 \)[/tex] (indicating this point is viable; Rory reaches sea level at this time).

### Summary:
After checking the points, we complete the table as follows:
\begin{center}
\begin{tabular}{|c|c|}
\hline
Time (t) & Elevation (e) \\
\hline
-2 & 320 \\
\hline
3.5 & 265.0 \\
\hline
30 & 0 \\
\hline
\end{tabular}
\end{center}

And in the summarized form:
[tex]\[ \begin{array}{l} a = 320 \checkmark \\ b = 265.0 \checkmark \\ c = 0 \end{array} \][/tex]