To determine the percentage of second-lunch students who eat outside, we need to analyze the data provided in the table.
1. Let's start by understanding the given data for both lunch periods:
- For the first lunch:
- Number of students eating outside is [tex]\(0.19\)[/tex].
- Number of students eating inside is [tex]\(0.26\)[/tex].
- Total number of students is [tex]\(0.45\)[/tex].
- For the second lunch:
- Number of students eating outside is [tex]\(0.21\)[/tex].
- Number of students eating inside is [tex]\(0.34\)[/tex].
- Total number of students is [tex]\(0.55\)[/tex].
2. Our objective is to find the percentage of second-lunch students who eat outside. The percentage can be calculated using the formula:
[tex]\[
\text{Percentage of second-lunch students who eat outside} = \left( \frac{\text{Number of students eating outside during the second lunch}}{\text{Total number of students during the second lunch}} \right) \times 100
\][/tex]
3. Substitute the given values into the formula:
[tex]\[
\text{Percentage of second-lunch students who eat outside} = \left( \frac{0.21}{0.55} \right) \times 100
\][/tex]
4. Perform the division to find the proportion:
[tex]\[
\frac{0.21}{0.55} \approx 0.3818181818181818
\][/tex]
5. Convert this proportion to a percentage:
[tex]\[
0.3818181818181818 \times 100 \approx 38.18181818181818
\][/tex]
6. Rounding this number to the nearest whole number results in approximately [tex]\( 38\% \)[/tex].
Comparing this percentage to the options provided:
- A. [tex]\( 38 \% \)[/tex]
- B. [tex]\( 45 \% \)[/tex]
- C. [tex]\( 21 \% \)[/tex]
- D. [tex]\( 55 \% \)[/tex]
The correct statement is:
A. A smaller percentage of second-lunch students ( [tex]$38 \%$[/tex] ) eat outside.
