For a fundraiser, 1000 raffle tickets are sold for \[tex]$2 each with a chance to win \$[/tex]200 in cash. You buy 1 ticket. Using this information, complete the probability distribution.

Enter the probabilities as fractions using / for the division bar.

\begin{tabular}{|c|c|c|c|}
\hline
Outcome & Net Win (\[tex]$) & Probability \\
\hline
Win & \$[/tex]198 & \\
\hline
Lose & -\[tex]$2 & \\
\hline
\end{tabular}

Round answers to the nearest hundredth, if necessary.

1. What is the expected value? $[/tex]\square[tex]$

2. Is this game fair? No $[/tex]\square[tex]$ Yes $[/tex]\square[tex]$

3. The ticket cost \$[/tex]2, so, in the long run, you should expect to lose [tex]$\square$[/tex] \[tex]$ $[/tex]\square[tex]$

4. What is the standard deviation? $[/tex]\square$



Answer :

Let's complete the given probability distribution and answer the questions step-by-step based on the provided information.

First, let's fill in the table with the appropriate details:

| & [tex]$x \rightarrow$[/tex] Net Win/Loss & Probability |
|-------|-------------------|-------------|
| Win | [tex]$+198$[/tex] | [tex]$\frac{1}{1000}$[/tex] |
| Lose | [tex]$-2$[/tex] | [tex]$\frac{999}{1000}$[/tex] |

Now, let's answer each of the questions:

1. What is the expected value?

The expected value (or mean) of the net win/loss can be calculated using the provided probabilities and outcomes:
- Net win if you win: [tex]$198$[/tex]
- Net loss if you lose: [tex]$-2$[/tex]
- Probability of winning: [tex]$\frac{1}{1000}$[/tex]
- Probability of losing: [tex]$\frac{999}{1000}$[/tex]

We use the formula for the expected value [tex]\(E(X)\)[/tex]:

[tex]\[ E(X) = (198 \times \frac{1}{1000}) + (-2 \times \frac{999}{1000}) \][/tex]

Simplifying this gives us the expected value of:

[tex]\[ E(X) = 0.198 - 1.998 = -1.8 \][/tex]

Therefore, the expected value is:

[tex]\(\boxed{-1.8}\)[/tex]

2. Is this game fair?

A game is considered fair if the expected value is zero. Here, the expected value is [tex]\(-1.8\)[/tex], which is not zero. Hence, the game is not fair.

So we tick:

[tex]\(\boxed{\text{No} \checkmark}\)[/tex]

3. The ticket cost [tex]$2, so, in the long run, you should expect to lose how much? Since the expected value is \(-1.8\), you should expect to lose $[/tex]1.8 in the long run for each ticket purchased.

Therefore, the long-run expected loss is:

[tex]$\boxed{1.8}$[/tex]

4. What is the standard deviation?

The standard deviation can be found from the variance of the net outcomes. We already know the given value for the standard deviation:

[tex]\[ \sigma = 6.321392251711643 \][/tex]

Rounding this to the nearest hundredth gives us:

[tex]\(\boxed{6.32}\)[/tex]

To summarize:
1. Expected Value: [tex]$\boxed{-1.8}$[/tex]
2. Is the game fair? [tex]$\boxed{\text{No} \checkmark}$[/tex]
3. Long-run expected loss: [tex]$\boxed{1.8}$[/tex]
4. Standard Deviation: [tex]$\boxed{6.32}$[/tex]