How many protons, neutrons, and electrons are in this ion?

[tex]\[
{ }_{20}^{46} \text{Ca}^{2+}
\][/tex]

A. [tex]\(20 p^{+}, 26 n^0, 22 e\)[/tex]

B. [tex]\(20 p^\ \textless \ em\ \textgreater \ , 26 n^{\circ}, 20 e\)[/tex]

C. [tex]\(20 p^\ \textless \ /em\ \textgreater \ , 26 n^0, 18 e\)[/tex]

D. [tex]\(23 p^*, 23 n^0, 21 e\)[/tex]



Answer :

To determine the number of protons, neutrons, and electrons in the ion [tex]\({ }_{20}^{46} Ca ^{2+}\)[/tex], follow these steps:

1. Identify the Number of Protons:
- The subscript of the ion ([tex]\(_{20}\)[/tex]) indicates the atomic number, which is the number of protons in the nucleus. Therefore, this ion has 20 protons.

2. Calculate the Number of Neutrons:
- The superscript of the ion ([tex]\(^{46}\)[/tex]) represents the mass number, which is the total number of protons and neutrons.
- Subtract the number of protons from the mass number to find the number of neutrons:
[tex]\[ \text{Number of neutrons} = 46 - 20 = 26 \][/tex]

3. Determine the Number of Electrons:
- For a neutral atom, the number of electrons is equal to the number of protons.
- However, this is a [tex]\(2+\)[/tex] ion, meaning it has lost 2 electrons. Therefore, the number of electrons is:
[tex]\[ \text{Number of electrons} = 20 - 2 = 18 \][/tex]

Summarizing these calculations, the ion [tex]\({ }_{20}^{46} Ca ^{2+}\)[/tex] has:
- 20 protons,
- 26 neutrons, and
- 18 electrons.

Therefore, the correct choice is:
[tex]\[ \boxed{20\ p^*,\ 26\ n^0,\ 18\ e} \][/tex]