To determine which ion was formed by providing the second ionization energy to remove an electron, let's carefully analyze the concept and the given ions.
The second ionization energy refers to the energy required to remove an electron from an ion that already has a +1 charge, producing an ion with a +2 charge. This means we are specifically looking for an ion with a +2 charge, as it results from removing an electron from a +1 charged ion.
Let's examine the ions provided:
1. [tex]\( \text{Ca}^{2+} \)[/tex]: This is a calcium ion with a +2 charge.
2. [tex]\( \text{N}^{3-} \)[/tex]: This is a nitrogen ion with a -3 charge.
3. [tex]\( \text{Fe}^{3+} \)[/tex]: This is an iron ion with a +3 charge.
4. [tex]\( \text{S}^{2-} \)[/tex]: This is a sulfur ion with a -2 charge.
From this list, the only ion that has a +2 charge is [tex]\( \text{Ca}^{2+} \)[/tex]. This indicates that calcium ion [tex]\( \text{Ca}^{2+} \)[/tex] is formed by providing the second ionization energy to remove an electron.
Therefore, the correct ion formed by providing the second ionization energy is [tex]\( \text{Ca}^{2+} \)[/tex], which is the first option.
