Absolutely, let's break down and complete these reactions methodically.
### Part (a):
Reactants: [tex]\( CH_3 - CH = CH - CH_3 \)[/tex] and [tex]\( Br_2 \)[/tex]
1. Identifying the Reactants:
- The organic molecule is 2-butene ([tex]\( CH_3 - CH = CH - CH_3 \)[/tex]).
- The other reactant is [tex]\( Br_2 \)[/tex] (Bromine).
2. Type of Reaction:
- This is an addition reaction where bromine additives across the double bond in the alkene.
3. Breaking the Double Bond:
- The π-bond in the 2-butene breaks and each carbon forms a new single bond (σ-bond) with a bromine atom.
4. Forming the Product:
- As bromine adds across the double bond, each carbon in the double bond will have one of the Br atoms attached, leading to the formation of 2,3-dibromobutane.
The balanced reaction is:
[tex]\[ CH_3 - CH = CH - CH_3 + Br_2 \longrightarrow CH_3 - CH(Br) - CH(Br) - CH_3 \][/tex]
### Part (b):
Reactants:
- An unspecified organic molecule.
- Chlorine gas ([tex]\( Cl_2 \)[/tex])
Since the specific organic molecule is not provided in the question, let's assume it is also an alkene similar to the example above as alkenes undergo similar addition reactions with halogens.
1. Assumption:
- Using a similar alkene, we'll assume it's ethylene ([tex]\( CH_2 = CH_2 \)[/tex]) for simplicity.
2. Type of Reaction:
- This is an addition reaction where chlorine is added across the double bond in the alkene.
3. Breaking the Double Bond:
- The π-bond in the ethylene breaks and each carbon forms new single bonds (σ-bonds) with the chlorine atoms.
4. Forming the Product:
- As chlorine adds across the double bond, each carbon in the initial double bond will have one of the Cl atoms attached, leading to the formation of 1,2-dichloroethane.
The balanced reaction assuming ethylene ([tex]\( CH_2 = CH_2 \)[/tex]) is:
[tex]\[ CH_2 = CH_2 + Cl_2 \longrightarrow CH_2Cl - CH_2Cl \][/tex]
If you provide a specific alkene for reaction (b), I can tailor the exact complete and balanced reaction accordingly.
