The following data values represent a sample. What is the variance of the sample? [tex]\(\bar{x}=9\)[/tex]. Use the information in the table to help you.

[tex]\[
\begin{tabular}{|c|c|c|c|c|c|}
\hline
$x$ & 7 & 15 & 11 & 1 & 11 \\
\hline
$\left(x_i-\bar{x}\right)^2$ & 4 & 36 & 4 & 64 & 4 \\
\hline
\end{tabular}
\][/tex]

A. 4.7
B. 22.4
C. 5.3
D. 28



Answer :

To determine the variance of the sample, we will follow a step-by-step approach:

1. Identify the sample mean ( [tex]\(\bar{x} \)[/tex]):
The sample mean ( [tex]\(\bar{x} \)[/tex]) is given as 9.

2. Identify the data values and their deviations squared ( [tex]\((x_i - \bar{x})^2 \)[/tex]):
The data values are [tex]\(7, 15, 11, 1, 11\)[/tex].
Their corresponding squared deviations from the sample mean are [tex]\(4, 36, 4, 64, 4\)[/tex].

3. Count the number of data values ( [tex]\(n \)[/tex]):
There are 5 data values.

4. Calculate the sample variance ( [tex]\(s^2 \)[/tex]):
The formula for sample variance is:
[tex]\[ s^2 = \frac{\sum (x_i - \bar{x})^2}{n - 1} \][/tex]
Here,
[tex]\[ \sum (x_i - \bar{x})^2 = 4 + 36 + 4 + 64 + 4 = 112 \][/tex]
So, we will divide this sum by [tex]\(n - 1\)[/tex], where [tex]\(n\)[/tex] is the number of data values:
[tex]\[ n - 1 = 5 - 1 = 4 \][/tex]

5. Calculate the variance:
[tex]\[ s^2 = \frac{112}{4} = 28 \][/tex]

Hence, the variance of the sample is 28.

The correct option is:
D. 28