tkabita338
Answered

Solve for [tex]\( x \)[/tex]:

[tex]\[
\frac{x+2}{x-2} = \frac{x-2}{x+2} = \frac{5}{6}
\][/tex]

---

Note: The equation given seems to imply two equalities which could be confusing. It might be more appropriate to separate them for clarity:

[tex]\[
\frac{x+2}{x-2} = \frac{5}{6} \quad \text{and} \quad \frac{x-2}{x+2} = \frac{5}{6}
\][/tex]



Answer :

GinnyAnswer
Sure! Let's solve the given equation step-by-step.

We start with the equation:

[tex]\[ \frac{x+2}{x-2} = \frac{5}{6} \][/tex]

To clear the fraction, we can use cross-multiplication:

[tex]\[ 6(x+2) = 5(x-2) \][/tex]

Now, let's distribute the constants on both sides:

[tex]\[ 6x + 12 = 5x - 10 \][/tex]

Next, we need to get all the [tex]\(x\)[/tex] terms on one side of the equation and the constant terms on the other side. Subtracting [tex]\(5x\)[/tex] from both sides, we get:

[tex]\[ 6x - 5x + 12 = -10 \][/tex]

Simplifying the left-hand side, we obtain:

[tex]\[ x + 12 = -10 \][/tex]

Next, we isolate [tex]\(x\)[/tex] by subtracting 12 from both sides:

[tex]\[ x = -22 \][/tex]

Therefore, the solution to the equation is:

[tex]\[ x = -22 \][/tex]

Other Questions