6. A wire 2,725 feet long and 85 mils in diameter has a resistance of 0.372 ohm. Find, to the nearest thousandth, the resistance of 3,600 feet of the same wire.

[tex] \frac{R_1}{R_2} = \frac{L_1}{L_2} \]



Answer :

Certainly! Let's solve the given problem step-by-step.

We are given:
- Length of the original wire, [tex]\( L_1 = 2725 \)[/tex] feet
- Resistance of the original wire, [tex]\( R_1 = 0.372 \)[/tex] ohms
- Length of the new wire, [tex]\( L_2 = 3600 \)[/tex] feet

We need to find the resistance of the new wire, [tex]\( R_2 \)[/tex].

Given the proportional relationship between resistance and wire length:

[tex]\[ \frac{R_1}{R_2} = \frac{L_1}{L_2} \][/tex]

We can rearrange this equation to solve for [tex]\( R_2 \)[/tex]:

[tex]\[ R_2 = R_1 \cdot \frac{L_2}{L_1} \][/tex]

Now, let's substitute the given values into the equation:

[tex]\[ R_2 = 0.372 \cdot \frac{3600}{2725} \][/tex]

Performing the calculation:

[tex]\[ R_2 = 0.372 \cdot 1.3211009174311927 \approx 0.491 \][/tex]

To the nearest thousandth, the resistance of the 3,600 feet of the same wire is:

[tex]\[ \boxed{0.491} \quad \text{ohms} \][/tex]