Let's calculate the volume percent ([tex]\( \%(v/v) \)[/tex]) of solute for each of the solutions separately.
### Solution 1: Methyl Alcohol
Given:
- Volume of methyl alcohol (solute): 18.7 mL
- Total volume of the solution: 515 mL
To calculate the volume percent of methyl alcohol in the solution, we use the following formula:
[tex]\[
\%(v/v) = \left( \frac{\text{Volume of solute}}{\text{Total volume of solution}} \right) \times 100
\][/tex]
Plugging in the given values:
[tex]\[
\%(v/v) = \left( \frac{18.7}{515} \right) \times 100
\][/tex]
The volume percent ([tex]\( \%(v/v) \)[/tex]) of methyl alcohol in the solution is:
[tex]\[
\%(v/v) \approx 3.63 \%
\][/tex]
### Solution 2: Ethylene Glycol
Given:
- Volume of ethylene glycol (solute): 76.1 mL
- Total volume of the solution: 227 mL
To calculate the volume percent of ethylene glycol in the solution, we use the same formula as above:
[tex]\[
\%(v/v) = \left( \frac{\text{Volume of solute}}{\text{Total volume of solution}} \right) \times 100
\][/tex]
Plugging in the given values:
[tex]\[
\%(v/v) = \left( \frac{76.1}{227} \right) \times 100
\][/tex]
The volume percent ([tex]\( \%(v/v) \)[/tex]) of ethylene glycol in the solution is:
[tex]\[
\%(v/v) \approx 33.52 \%
\][/tex]
### Summary
- The volume percent of methyl alcohol in the first solution is approximately [tex]\(3.63\% \)[/tex].
- The volume percent of ethylene glycol in the second solution is approximately [tex]\(33.52\% \)[/tex].
