To determine how many moles of NaOH are present in 30.0 mL of 0.140 M NaOH, follow these steps:
1. Convert the volume from milliliters to liters:
[tex]\[
1 \text{ liter (L)} = 1000 \text{ milliliters (mL)}
\][/tex]
Given volume is 30.0 mL. Therefore,
[tex]\[
\text{Volume in liters (L)} = \frac{30.0 \text{ mL}}{1000} = 0.03 \text{ L}
\][/tex]
2. Use the molarity (M) to find the number of moles:
Molarity (M) is defined as the number of moles of solute per liter of solution.
Given:
[tex]\[
\text{Concentration} (M) = 0.140 \text{ M}
\][/tex]
Therefore, the number of moles of NaOH can be calculated using the formula:
[tex]\[
\text{Moles of NaOH} = \text{Concentration (M)} \times \text{Volume (L)}
\][/tex]
Substituting the given values:
[tex]\[
\text{Moles of NaOH} = 0.140 \text{ M} \times 0.03 \text{ L} = 0.0042 \text{ mol}
\][/tex]
So, the number of moles of NaOH present in 30.0 mL of 0.140 M NaOH is:
[tex]\[
\boxed{0.0042 \text{ mol}}
\][/tex]
