Instructions: Factor the given polynomial and find the rational zeros. Enter the zeros from LEAST to GREATEST.

[tex]\[ f(x) = x^3 - 5x^2 + 4x \][/tex]

Zeros: [tex]\[\square \quad \square \quad \square\][/tex]



Answer :

To factor the cubic polynomial [tex]\( f(x) = x^3 - 5x^2 + 4x \)[/tex] and find its rational zeros, we will follow these steps:

### Step 1: Factor the Polynomial
First, we look for common factors in the polynomial [tex]\( f(x) = x^3 - 5x^2 + 4x \)[/tex].

Notice that each term in the polynomial contains an [tex]\( x \)[/tex]. So, we can factor out an [tex]\( x \)[/tex] from the entire polynomial:
[tex]\[ f(x) = x(x^2 - 5x + 4) \][/tex]

Next, we need to factor the quadratic part [tex]\( x^2 - 5x + 4 \)[/tex]. To do this, we look for two numbers that multiply to the constant term (4) and add up to the coefficient of the linear term (-5).

The two numbers that satisfy these conditions are -1 and -4 because:
[tex]\[ -1 \times -4 = 4 \][/tex]
[tex]\[ -1 + (-4) = -5 \][/tex]

Thus, the quadratic part can be factored as:
[tex]\[ x^2 - 5x + 4 = (x - 1)(x - 4) \][/tex]

So, the complete factorization of the polynomial [tex]\( f(x) \)[/tex] is:
[tex]\[ f(x) = x(x - 1)(x - 4) \][/tex]

### Step 2: Find the Rational Zeros
The rational zeros of a polynomial are the values of [tex]\( x \)[/tex] that make the polynomial equal to zero. To find these zeros, we set each factor equal to zero:

1. [tex]\( x = 0 \)[/tex]
2. [tex]\( x - 1 = 0 \)[/tex] \rightarrow [tex]\( x = 1 \)[/tex]
3. [tex]\( x - 4 = 0 \)[/tex] \rightarrow [tex]\( x = 4 \)[/tex]

### Step 3: Sort the Zeros from Least to Greatest
We list the zeros we found in ascending order:
[tex]\[ 0, 1, 4 \][/tex]

### Final Answer:
Zeros: [tex]\( 0 \)[/tex], [tex]\( 1 \)[/tex], [tex]\( 4 \)[/tex]