\begin{tabular}{|c|c|c|c|c|}
\hline
\begin{tabular}{c}
Number of \\
Protons
\end{tabular} & \begin{tabular}{c}
Number of \\
Neutrons
\end{tabular} & \begin{tabular}{c}
Atomic \\
Number
\end{tabular} & \begin{tabular}{c}
Mass \\
Number
\end{tabular} & \begin{tabular}{c}
Element \\
(symbol)
\end{tabular} \\
\hline
A & 7 & B & 15 & C \\
\hline
D & E & 26 & 56 & F \\
\hline
\end{tabular}

Using the periodic table, complete the table to describe each atom. Type in your answers.

A [tex]$\square$[/tex] \\
B [tex]$\square$[/tex] \\
C [tex]$\square$[/tex] \\
D [tex]$\square$[/tex] \\
E [tex]$\square$[/tex]



Answer :

To complete the table, let's follow the steps for each row.

### Row 1
1. Mass number (given as 15) is the sum of the number of protons (A) and the number of neutrons (7).
- Mass number = Number of protons (A) + Number of Neutrons
- 15 = A + 7
- Solving for A:
[tex]\( A = 15 - 7 \)[/tex]
[tex]\( A = 8 \)[/tex]

2. Atomic number is always equal to the number of protons:
- B = A
- Thus, [tex]\( B = 8 \)[/tex]

3. Using the periodic table, the element with an atomic number of 8 is Oxygen (O):
- C = "O"

### Row 2
1. Atomic number is given as 26, indicating the element is Iron (Fe).
- D is the atomic number:
[tex]\( D = 26 \)[/tex]

2. Using the periodic table, the element with atomic number 26 is Iron (Fe):
- F = "Fe"

3. Mass number (given as 56) is the sum of the number of protons (26) and the number of neutrons (E).
- Mass number = Number of protons (26) + Number of Neutrons (E)
- 56 = 26 + E
- Solving for E:
[tex]\( E = 56 - 26 \)[/tex]
[tex]\( E = 30 \)[/tex]

After filling out the table, the values for the blanks are:

- A: 8
- B: 8
- C: "O"
- D: 26
- E: 30
- F: "Fe"

So, the completed table is:

\begin{tabular}{|c|c|c|c|c|}
\hline
\begin{tabular}{c}
Number of \\
Protons
\end{tabular} & \begin{tabular}{c}
Number of \\
Neutrons
\end{tabular} & \begin{tabular}{c}
Atomic \\
Number
\end{tabular} & \begin{tabular}{c}
Mass \\
Number
\end{tabular} & \begin{tabular}{c}
Element \\
(symbol)
\end{tabular} \\
\hline
8 & 7 & 8 & 15 & O \\
\hline
26 & 30 & 26 & 56 & Fe \\
\hline
\end{tabular}