Suppose a product's revenue function is given by [tex] R(q) = -2q^2 + 500q [/tex], where [tex] R(q) [/tex] is in dollars and [tex] q [/tex] is units sold. Find the rate at which revenue changes when 165 units are sold.

Which best interprets your previous answer? (Choose one)

A. When 165 units are sold, revenue decreases by \[tex]$160.
B. \$[/tex]160 are lost for each unit sold after 165 units.
C. Revenue decreases by 160 units per dollar when cost is \[tex]$165.
D. Revenue increases by \$[/tex]160 per unit when 165 units are sold.
E. Revenue is decreasing by \$160 per unit when 165 units are sold.



Answer :

To determine the rate at which revenue changes when 165 units are sold, follow these steps:

1. Identify the Revenue Function:
The revenue function is [tex]\( R(q) = -2q^2 + 500q \)[/tex], where [tex]\( R(q) \)[/tex] is the revenue in dollars and [tex]\( q \)[/tex] is the number of units sold.

2. Find the First Derivative of the Revenue Function:
The first derivative of [tex]\( R(q) \)[/tex] with respect to [tex]\( q \)[/tex], denoted [tex]\( R'(q) \)[/tex], represents the rate of change of revenue with respect to the number of units sold. It is given by:
[tex]\[ R'(q) = \frac{d}{dq}(-2q^2 + 500q) \][/tex]

Calculating the derivative, we get:
[tex]\[ R'(q) = -4q + 500 \][/tex]

3. Evaluate the Derivative at [tex]\( q = 165 \)[/tex]:
To find the rate of change of revenue when 165 units are sold, substitute [tex]\( q = 165 \)[/tex] into [tex]\( R'(q) \)[/tex]:
[tex]\[ R'(165) = -4(165) + 500 \][/tex]

Performing the arithmetic:
[tex]\[ R'(165) = -660 + 500 = -160 \][/tex]

4. Interpret the Result:
The value [tex]\( R'(165) = -160 \)[/tex] means that the revenue is decreasing at a rate of 160 dollars per unit when 165 units are sold.

Thus, the correct interpretation of the result is:

- revenue is decreasing by 160 dollars per unit when 165 units are sold