Answer :
Sure, let's tackle this problem step by step.
### Given Information:
- Class A has 100 students.
- Class B has 100 students.
- Nadia surveyed 10% of Class A.
- Nadia also surveyed 70% of Class B.
### Step 1: Calculate the Number of Students Surveyed in Each Class
Class A:
- The number of students surveyed in Class A = 10% of 100
[tex]\[ \text{Class A surveyed} = \frac{10}{100} \times 100 = 10 \][/tex]
Class B:
- The number of students surveyed in Class B = 70% of 100
[tex]\[ \text{Class B surveyed} = \frac{70}{100} \times 100 = 70 \][/tex]
### Step 2: Total Number of Students Surveyed
[tex]\[ \text{Total students surveyed} = \text{Class A surveyed} + \text{Class B surveyed} = 10 + 70 = 80 \][/tex]
### Step 3: Total Number of Students in Both Classes
[tex]\[ \text{Total students} = \text{Class A students} + \text{Class B students} = 100 + 100 = 200 \][/tex]
### Step 4: Percentage of Total Students Surveyed
To find the percentage of the total number of students surveyed:
[tex]\[ \text{Percentage surveyed} = \left( \frac{\text{Total students surveyed}}{\text{Total students}} \right) \times 100 \][/tex]
[tex]\[ \text{Percentage surveyed} = \left( \frac{80}{200} \right) \times 100 = 40\% \][/tex]
### Part (a)
Nadia claimed that [tex]\(10\% + 70\% = 80\%\)[/tex] of the total students were surveyed. Let's check this:
Nadia's Claim:
- She claimed that 80% of the total students in both classes were surveyed.
- However, we calculated that only 40% of the total students were surveyed.
Conclusion:
Nadia's claim is incorrect because only 40% of the total students were actually surveyed, not 80%.
### Part (b)
Raju's approach involved taking the average of the percentages:
[tex]\[ \text{Raju's calculation} = \frac{10\% + 70\%}{2} = \frac{80\%}{2} = 40\% \][/tex]
Raju's Claim:
- He claimed that 40% of the total students in both classes were surveyed.
- Our calculation confirms that indeed 40% of the total students were surveyed.
Conclusion:
Raju's claim is correct because 40% of the total number of students were actually surveyed, which matches his calculation.
### Given Information:
- Class A has 100 students.
- Class B has 100 students.
- Nadia surveyed 10% of Class A.
- Nadia also surveyed 70% of Class B.
### Step 1: Calculate the Number of Students Surveyed in Each Class
Class A:
- The number of students surveyed in Class A = 10% of 100
[tex]\[ \text{Class A surveyed} = \frac{10}{100} \times 100 = 10 \][/tex]
Class B:
- The number of students surveyed in Class B = 70% of 100
[tex]\[ \text{Class B surveyed} = \frac{70}{100} \times 100 = 70 \][/tex]
### Step 2: Total Number of Students Surveyed
[tex]\[ \text{Total students surveyed} = \text{Class A surveyed} + \text{Class B surveyed} = 10 + 70 = 80 \][/tex]
### Step 3: Total Number of Students in Both Classes
[tex]\[ \text{Total students} = \text{Class A students} + \text{Class B students} = 100 + 100 = 200 \][/tex]
### Step 4: Percentage of Total Students Surveyed
To find the percentage of the total number of students surveyed:
[tex]\[ \text{Percentage surveyed} = \left( \frac{\text{Total students surveyed}}{\text{Total students}} \right) \times 100 \][/tex]
[tex]\[ \text{Percentage surveyed} = \left( \frac{80}{200} \right) \times 100 = 40\% \][/tex]
### Part (a)
Nadia claimed that [tex]\(10\% + 70\% = 80\%\)[/tex] of the total students were surveyed. Let's check this:
Nadia's Claim:
- She claimed that 80% of the total students in both classes were surveyed.
- However, we calculated that only 40% of the total students were surveyed.
Conclusion:
Nadia's claim is incorrect because only 40% of the total students were actually surveyed, not 80%.
### Part (b)
Raju's approach involved taking the average of the percentages:
[tex]\[ \text{Raju's calculation} = \frac{10\% + 70\%}{2} = \frac{80\%}{2} = 40\% \][/tex]
Raju's Claim:
- He claimed that 40% of the total students in both classes were surveyed.
- Our calculation confirms that indeed 40% of the total students were surveyed.
Conclusion:
Raju's claim is correct because 40% of the total number of students were actually surveyed, which matches his calculation.