What is the equation in point-slope form of the line that passes through the point [tex](-1, -3)[/tex] and has a slope of 4?

A. [tex]y - 3 = 4(x - 1)[/tex]
B. [tex]y + 1 = 4(x + 3)[/tex]
C. [tex]y + 3 = 4(x + 1)[/tex]
D. [tex]y - 1 = 4(x - 3)[/tex]



Answer :

Certainly! To find the equation of a line using the point-slope form, we use the formula:

[tex]\[ y - y_1 = m(x - x_1) \][/tex]

where [tex]\((x_1, y_1)\)[/tex] is a point on the line, and [tex]\(m\)[/tex] is the slope of the line.

Given:
- Point: [tex]\((-1, -3)\)[/tex]
- Slope: [tex]\(4\)[/tex]

Let's substitute these values into the point-slope formula:

1. Substitute [tex]\(x_1 = -1\)[/tex], [tex]\(y_1 = -3\)[/tex], and [tex]\(m = 4\)[/tex] into the formula:

[tex]\[ y - (-3) = 4(x - (-1)) \][/tex]

2. Simplify the equation:

[tex]\[ y + 3 = 4(x + 1) \][/tex]

Thus, the equation of the line in point-slope form is:

[tex]\[ y + 3 = 4(x + 1) \][/tex]

From the given options, the correct one is:

[tex]\[ y + 3 = 4(x + 1) \][/tex]