To find the effective (RMS) voltage value of a circuit that has a peak voltage of 310V, you can use the following formula:
[tex]\[ V_\text{rms} = \frac{V_\text{peak}}{\sqrt{2}} \][/tex]
Let's go through the steps together:
1. Understand the given value:
- The peak voltage [tex]\( V_\text{peak} \)[/tex] is 310V.
2. Apply the formula:
- The formula for converting peak voltage to RMS voltage is [tex]\( V_\text{rms} = \frac{V_\text{peak}}{\sqrt{2}} \)[/tex].
3. Substitute the peak voltage into the formula:
- Substituting 310V for [tex]\( V_\text{peak} \)[/tex]:
[tex]\[ V_\text{rms} = \frac{310}{\sqrt{2}} \][/tex]
4. Calculate the RMS voltage:
- Perform the division to get the RMS value.
Thus, the approximate effective voltage value of the circuit is 219V.
Among the given options, the correct answer is:
O 219V
