Type the correct answer in the box. Use numerals instead of words.

A toy is being constructed in the shape of a pyramid. The maximum amount of material to cover the sides and bottom of the pyramid is 250 square centimeters. The height of the toy is double the side length. What are the maximum dimensions to the nearest square centimeter for a square base and for a hexagonal base?

\begin{tabular}{|c|c|c|}
\hline
Shape of Base & Side Length & Height \\
\hline
Square & [tex]$\square \, \text{cm}$[/tex] & [tex]$\square \, \text{cm}$[/tex] \\
\hline
Regular Hexagon & [tex]$\square \, \text{cm}$[/tex] & [tex]$\square \, \text{cm}$[/tex] \\
\hline
\end{tabular}



Answer :

To determine the maximum dimensions of the toy pyramid with a material limit of 250 square centimeters and a height that is double the side length, let's consider both a square base and a hexagonal base.

### 1. Square Base
For a pyramid with a square base:
- Let the side length of the square base be [tex]\( s \)[/tex] cm.
- The height of the pyramid is [tex]\( h \)[/tex] cm.
- Given that the height [tex]\( h \)[/tex] is double the side length [tex]\( s \)[/tex], we have [tex]\( h = 2s \)[/tex].

We'll solve for [tex]\( s \)[/tex]:

#### Solution:
- Side Length for Square base: [tex]\( 7 \)[/tex] cm
- Height for Square base: [tex]\( 14 \)[/tex] cm

### 2. Hexagonal Base
For a pyramid with a hexagonal base:
- Let the side length of the hexagonal base be [tex]\( s \)[/tex] cm.
- The height of the pyramid is [tex]\( h \)[/tex] cm.
- Given that the height [tex]\( h \)[/tex] is double the side length [tex]\( s \)[/tex], we have [tex]\( h = 2s \)[/tex].

We'll solve for [tex]\( s \)[/tex]:

#### Solution:
- Side Length for Hexagonal base: [tex]\( 5 \)[/tex] cm
- Height for Hexagonal base: [tex]\( 11 \)[/tex] cm

[tex]\[ \begin{tabular}{|c|c|c|} \hline Shape of Base & Side Length & Height \\ \hline square & 7 \, \text{cm} & 14 \, \text{cm} \\ \hline regular hexagon & 5 \, \text{cm} & 11 \, \text{cm} \\ \hline \end{tabular} \][/tex]