Last year, Milwaukee had a total snowfall amounting to 92 inches. The normal snowfall is [tex]$52 \frac{1}{4}$[/tex] inches. How much above normal was the snowfall last year?



Answer :

To determine how much above normal the snowfall was last year in Milwaukee, we can follow these steps:

1. Identify the snowfall from last year: The total snowfall last year was 92 inches.
2. Determine the normal snowfall: The normal fall is [tex]\( 52 \frac{1}{4} \)[/tex] inches, which can be converted to a decimal. The mixed number [tex]\( 52 \frac{1}{4} \)[/tex] is equivalent to [tex]\( 52 + 0.25 \)[/tex] or 52.25 inches.
3. Calculate the difference: To find out how much above normal the snowfall was last year, subtract the normal snowfall from the last year's snowfall.

[tex]\[ \text{Difference} = \text{Last Year's Snowfall} - \text{Normal Snowfall} \][/tex]
Substituting the values:

[tex]\[ \text{Difference} = 92\ \text{inches} - 52.25\ \text{inches} \][/tex]
4. Perform the subtraction:

[tex]\[ 92 - 52.25 = 39.75\ \text{inches} \][/tex]

Therefore, the snowfall last year was 39.75 inches above normal.