At the beginning of year 1, Zack invests [tex]$\$ 700$[/tex] at an annual compound interest rate of [tex]$3\%$[/tex]. He makes no deposits to or withdrawals from the account.

Which explicit formula can be used to find the account's balance at the beginning of year 5? What is the balance?

A. [tex]$A(n)=700+(n-1)(0.03 \cdot 700)[tex]$ ; \$[/tex] 784.00[/tex]
B. [tex]$A(n)=700+(0.003 \cdot 700)^{(n-1)}$ ; \$ 719.45[/tex]
C. [tex]$A(n)=700 \cdot(1+0.03)^{(n-1)}[tex]$ ; \$[/tex] 787.86[/tex]
D. [tex]$A(n)=700 \cdot(1+0.03)^n$ ; \$ 811.49[/tex]



Answer :

To determine the correct explicit formula and the balance at the beginning of year 5 for Zack's investment, let's analyze each given option.

1. Understanding the compound interest formula:
Compound interest calculated annually follows the formula:
[tex]\[ A = P \left(1 + \frac{r}{100}\right)^n \][/tex]
Where:
- [tex]\(A\)[/tex] = the amount of money accumulated after n years, including interest.
- [tex]\(P\)[/tex] = the principal amount (the initial amount of money).
- [tex]\(r\)[/tex] = the annual interest rate (as a decimal).
- [tex]\(n\)[/tex] = the number of years the money is invested or borrowed for.

Given:
- Principal ([tex]\(P\)[/tex]) = \[tex]$700 - Annual interest rate (\(r\)) = 3% or 0.03 as a decimal. - Number of years (\(n\)) = 5 Let's evaluate each option: Option A: \(A(n) = 700 + (n-1)(0.03 \cdot 700)\) - This formula represents a linear growth model, not compound interest. - At \(n = 5\), this gives: \[ A(5) = 700 + (5-1)(0.03 \cdot 700) = 700 + 4 \cdot 21 = 700 + 84 = 784 \] - The balance is \$[/tex]784.00, which matches the given value but does not use the compound interest model.

Option B: [tex]\(A(n) = 700 + (0.003 \cdot 700)^{(n-1)}\)[/tex]

- This formula incorrectly represents the growth factor and exponentiation.
- At [tex]\(n = 5\)[/tex], this gives:
[tex]\[ A(5) = 700 + (0.003 \cdot 700)^{4} = 700 + 201.45 = 719.45 \][/tex]
- The balance is \[tex]$719.45, which does not reflect the compound interest model. Option C: \(A(n) = 700 \cdot (1 + 0.03)^{(n-1)}\) - This formula uses the correct compound interest concept but starts from year 1. - At \(n = 5\), this gives: \[ A(5) = 700 \cdot (1 + 0.03)^{4} = 700 \cdot 1.1255 = 787.86 \] - The balance is \$[/tex]787.86, which is close but isn't the compound interest calculation for the end of year 5.

Option D: [tex]\(A(n) = 700 \cdot (1 + 0.03)^n\)[/tex]

- This formula correctly represents the compound interest calculation from the beginning.
- At [tex]\(n = 5\)[/tex], this gives:
[tex]\[ A(5) = 700 \cdot (1 + 0.03)^5 = 700 \cdot 1.159274 = 811.49 \][/tex]
- The balance is \[tex]$811.49, which accurately represents the compound interest after 5 full years. Thus, the correct explicit formula to find the account’s balance at the beginning of year 5 is: \[ \boxed{A(n) = 700 \cdot (1 + 0.03)^n} \] And the balance is: \[ \boxed{\$[/tex]811.49}
\]