Calculate the density of a block of iron.

Given:
- Mass of the block: 3152 kg
- Volume of the block: [tex]0.4 \, m^3[/tex]

Use the formula:
[tex] \text{density} = \frac{\text{mass}}{\text{volume}} [/tex]

Calculate the density in [tex] kg/m^3 [/tex]. If your answer is a decimal, round it to one decimal place.



Answer :

To calculate the density of a block of iron given its mass and volume, follow these steps:

1. Identify the given values:
- Mass ([tex]\( m \)[/tex]) = 3152 kg
- Volume ([tex]\( V \)[/tex]) = 0.4 m[tex]\(^3\)[/tex]

2. Write down the density formula:

[tex]\[ \text{Density} (\rho) = \frac{\text{Mass} (m)}{\text{Volume} (V)} \][/tex]

3. Substitute the given values into the formula:

[tex]\[ \rho = \frac{3152 \, \text{kg}}{0.4 \, \text{m}^3} \][/tex]

4. Calculate the density:

[tex]\[ \rho = 7880 \, \text{kg} / \text{m}^3 \][/tex]

5. Round the answer to 1 decimal place (if necessary):

Since the value obtained for density is [tex]\( 7880.0 \, \text{kg} / \text{m}^3 \)[/tex], it already is a whole number. When rounded to 1 decimal place, it remains:

[tex]\[ \rho \approx 7880.0 \, \text{kg} / \text{m}^3 \][/tex]

So, the density of the block of iron is [tex]\( 7880.0 \, \text{kg} / \text{m}^3 \)[/tex].