Given the formula:

[tex]\[ \text{pressure} = \frac{\text{force}}{\text{area}} \][/tex]

The pressure exerted on a table by a brick is [tex]\( 270 \, \text{N/m}^2 \)[/tex] and the area of the base of the brick is [tex]\( 0.03 \, \text{m}^2 \)[/tex].

Calculate the force, in N, that the brick exerts on the table. If your answer is a decimal, give it to 1 decimal place.



Answer :

To find the force that the brick exerts on the table, we can use the relationship between pressure, force, and area given by the formula:

[tex]\[ \text{Pressure} = \frac{\text{Force}}{\text{Area}} \][/tex]

We're provided with the pressure and the area of the base of the brick. We need to solve for the force. Rearrange the formula to solve for force:

[tex]\[ \text{Force} = \text{Pressure} \times \text{Area} \][/tex]

Substitute the given values into the equation:

- Pressure ([tex]\(P\)[/tex]) = 270 N/m²
- Area ([tex]\(A\)[/tex]) = 0.03 m²

[tex]\[ \text{Force} = 270 \, \text{N/m}^2 \times 0.03 \, \text{m}^2 \][/tex]

Now, perform the multiplication:

[tex]\[ \text{Force} = 270 \times 0.03 = 8.1 \, \text{N} \][/tex]

Therefore, the force that the brick exerts on the table is [tex]\(8.1 \, \text{N}\)[/tex].