Answer :

To simplify the given expression [tex]\(\sqrt{4 x^2} + \sqrt{16 x^3}\)[/tex] step-by-step, we'll break it down into more manageable parts.

### Step 1: Simplify each square root separately

1. Simplify [tex]\(\sqrt{4 x^2}\)[/tex]:
- Recall that [tex]\(\sqrt{a^2} = a\)[/tex] if [tex]\(a \geq 0\)[/tex].
- Here, we can write [tex]\(4 x^2\)[/tex] as [tex]\((2 x)^2\)[/tex].
- Applying the square root, we get:
[tex]\[ \sqrt{4 x^2} = \sqrt{(2 x)^2} = 2 x \][/tex]

2. Simplify [tex]\(\sqrt{16 x^3}\)[/tex]:
- We can factor [tex]\(\sqrt{16 x^3}\)[/tex] into simpler components.
- Notice that [tex]\(16 x^3 = 16 x^2 \cdot x\)[/tex].
- We know that [tex]\(\sqrt{16 x^2} = 4 x\)[/tex], because [tex]\(\sqrt{16 x^2} = \sqrt{(4 x)^2} = 4 x\)[/tex].
[tex]\[ \sqrt{16 x^3} = \sqrt{16 x^2 \cdot x} = \sqrt{16 x^2} \cdot \sqrt{x} = 4 x \cdot \sqrt{x} = 4 \sqrt{x^3} \][/tex]

### Step 2: Combine the simplified expressions

Having simplified both components separately, we can now combine them:
[tex]\[ \sqrt{4 x^2} + \sqrt{16 x^3} = 2x + 4\sqrt{x^3} \][/tex]

Expressing [tex]\(\sqrt{x^3}\)[/tex] with rational exponents:
[tex]\[ \sqrt{x^3} = x^{3/2} \][/tex]
So, we have:
[tex]\[ 2 x + 4 x^{3/2} \][/tex]

Therefore, the simplified form of the given expression [tex]\(\sqrt{4 x^2} + \sqrt{16 x^3}\)[/tex] is:
[tex]\[ 2 x + 4 x^{3/2} \][/tex]

For more clarity, this provides a result consistent with the following form:
[tex]\[ 2 \sqrt{x^2} + 4 \sqrt{x^3} \][/tex]

In conclusion, the simplified expression is:
[tex]\[ 2\sqrt{x^2} + 4\sqrt{x^3} \][/tex]