Find the area of a regular polygon with 12 sides, an apothem of 16 meters, and a side length of 8.6 meters.

[tex]\[ A = \text{?} \, m^2 \][/tex]



Answer :

To find the area of a regular polygon, such as the one described with 12 sides, an apothem of 16 meters, and a side length of 8.6 meters, we can follow these steps:

1. Determine the Perimeter of the Polygon:

The perimeter of a polygon is the sum of the lengths of all its sides. Since it is a regular polygon with 12 sides, each of which is 8.6 meters long, we can calculate the perimeter by multiplying the number of sides by the length of one side.

[tex]\[ \text{Perimeter} = \text{number of sides} \times \text{length of one side} \][/tex]

[tex]\[ \text{Perimeter} = 12 \times 8.6 = 103.2 \text{ meters} \][/tex]

2. Calculate the Area of the Polygon:

The area [tex]\(A\)[/tex] of a regular polygon can be calculated using the formula:

[tex]\[ A = \frac{1}{2} \times \text{Perimeter} \times \text{Apothem} \][/tex]

Substituting the perimeter and apothem we calculated into the formula gives:

[tex]\[ A = \frac{1}{2} \times 103.2 \times 16 \][/tex]

Simplifying further, we get:

[tex]\[ A = 0.5 \times 103.2 \times 16 = 825.6 \text{ square meters} \][/tex]

Therefore, the area of the regular polygon is [tex]\(825.6 \text{ m}^2\)[/tex].