Sure, let's break down the given problem step-by-step.
### First Scenario:
If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, what is the chance that the offspring will be heterozygous?
1. Parental Genotypes:
- Male: Ww
- Female: ww
2. Punnett Square:
- Male (Ww) can contribute either W or w.
- Female (ww) can only contribute w.
The Punnett square looks like this:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\][/tex]
3. Possible Offspring Genotypes:
- Ww
- Ww
- ww
- ww
Thus, there's a 50% chance (2 out of 4) that the offspring will be heterozygous (Ww).
### Second Scenario:
If the heterozygous Ww is crossed with a homozygous dominant WW, what is the probability of having a homozygous recessive offspring?
1. Parental Genotypes:
- Heterozygous: Ww
- Homozygous dominant: WW
2. Punnett Square:
- Heterozygous Ww can contribute either W or w.
- Homozygous dominant WW can only contribute W.
The Punnett square looks like this:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline W & WW & Ww \\
\hline W & WW & Ww \\
\hline
\end{array}
\][/tex]
3. Possible Offspring Genotypes:
- WW
- WW
- Ww
- Ww
There are no homozygous recessive (ww) offspring in this scenario. Hence, the probability is 0%.
### Answer Summary:
1. If a heterozygous male (Ww) is mated with a homozygous recessive female (ww), there is a 50% chance that the offspring will be heterozygous (Ww).
2. If a heterozygous (Ww) is crossed with a homozygous dominant (WW), the probability of having a homozygous recessive (ww) offspring is 0.
