A large diamond with a mass of 2138.7 grams was recently discovered in a mine. If the density of the diamond is [tex]$3.51 \frac{ g }{ cm ^3}$[/tex], what is the volume? Round your answer to the nearest hundredth.

A. [tex]$141.84 \, cm^3$[/tex]

B. [tex][tex]$609.32 \, cm^3$[/tex][/tex]

C. [tex]$717.06 \, cm^3$[/tex]

D. [tex]$8169.8 \, cm^3$[/tex]



Answer :

To find the volume of a diamond given its mass and density, we can use the formula for density:

[tex]\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \][/tex]

Rearranging the formula to solve for volume, we get:

[tex]\[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \][/tex]

Given:
- Mass of the diamond, [tex]\( \text{Mass} = 2138.7 \)[/tex] grams
- Density of the diamond, [tex]\( \text{Density} = 3.51 \, \frac{\text{g}}{\text{cm}^3} \)[/tex]

Substitute these values into the formula:

[tex]\[ \text{Volume} = \frac{2138.7 \, \text{g}}{3.51 \, \frac{\text{g}}{\text{cm}^3}} \][/tex]

Calculate the volume:

[tex]\[ \text{Volume} \approx 609.3162393162393 \, \text{cm}^3 \][/tex]

Next, round this volume to the nearest hundredth:

[tex]\[ \text{Volume} \approx 609.32 \, \text{cm}^3 \][/tex]

So, the volume of the diamond is:

[tex]\[ \boxed{609.32 \, \text{cm}^3} \][/tex]