A table of the visible light spectrum is shown below.

\begin{tabular}{|c|c|}
\hline Color & \begin{tabular}{c}
Wavelength \\
[tex]$( nm )$[/tex]
\end{tabular} \\
\hline Red & [tex]$700-635$[/tex] \\
\hline Orange & [tex]$635-590$[/tex] \\
\hline Yellow & [tex]$590-560$[/tex] \\
\hline Green & [tex]$560-490$[/tex] \\
\hline Blue & [tex]$490-450$[/tex] \\
\hline Purple & [tex]$450-400$[/tex] \\
\hline
\end{tabular}

Tyrone analyzes the emission spectrum of an unknown element. He observes two discrete lines at 600 nm and 650 nm, and he sees many lines corresponding to shorter wavelengths, with the strongest line being at 475 nm.

Which emission spectrum is Tyrone most likely analyzing?



Answer :

To determine which emission spectrum Tyrone is most likely analyzing, we need to match the observed wavelengths to the corresponding colors in the visible light spectrum table provided.

The observed wavelengths are:
1. 600 nm
2. 650 nm
3. 475 nm

Let's determine the color for each observed wavelength based on the given wavelength ranges for each color:

1. 600 nm:
- The range for Red is 700-635 nm.
- The range for Orange is 635-590 nm.
- 600 nm falls within the range of 635-590 nm, so the color corresponding to 600 nm is Orange.

2. 650 nm:
- The range for Red is 700-635 nm.
- 650 nm falls within the range of 700-635 nm, so the color corresponding to 650 nm is Red.

3. 475 nm:
- The range for Purple is 450-400 nm.
- The range for Blue is 490-450 nm.
- 475 nm falls within the range of 490-450 nm, so the color corresponding to 475 nm is Blue.

Based on these observations, Tyrone analyzes an unknown element's emission spectrum and observes the following colors:
1. 600 nm - Orange
2. 650 nm - Red
3. 475 nm - Blue

Hence, Tyrone is most likely analyzing an emission spectrum with the observed lines corresponding to the colors Orange, Red, and Blue.