Determine the intercepts of the graph of [tex]-\frac{x}{10}+\frac{y}{8}=1[/tex]. Then draw an accurate graph of the linear equation.

- [tex]x[/tex]-intercept: [tex]\square[/tex]
- [tex]y[/tex]-intercept: [tex]\square[/tex]



Answer :

Sure, let's determine the intercepts of the linear equation [tex]\(-\frac{x}{10} + \frac{y}{8} = 1\)[/tex].

Step 1: Finding the [tex]\(x\)[/tex]-intercept

The [tex]\(x\)[/tex]-intercept is found by setting [tex]\(y = 0\)[/tex] and solving for [tex]\(x\)[/tex].

1. Substitute [tex]\(y = 0\)[/tex] into the equation:
[tex]\[ -\frac{x}{10} + \frac{0}{8} = 1 \][/tex]
2. Simplify the equation:
[tex]\[ -\frac{x}{10} = 1 \][/tex]
3. Solve for [tex]\(x\)[/tex]:
[tex]\[ x = -10 \][/tex]

Therefore, the [tex]\(x\)[/tex]-intercept is [tex]\(-10\)[/tex].

Step 2: Finding the [tex]\(y\)[/tex]-intercept

The [tex]\(y\)[/tex]-intercept is found by setting [tex]\(x = 0\)[/tex] and solving for [tex]\(y\)[/tex].

1. Substitute [tex]\(x = 0\)[/tex] into the equation:
[tex]\[ -\frac{0}{10} + \frac{y}{8} = 1 \][/tex]
2. Simplify the equation:
[tex]\[ \frac{y}{8} = 1 \][/tex]
3. Solve for [tex]\(y\)[/tex]:
[tex]\[ y = 8 \][/tex]

Therefore, the [tex]\(y\)[/tex]-intercept is [tex]\(8\)[/tex].

Summary

- [tex]\(x\)[/tex]-intercept: [tex]\(-10\)[/tex]
- [tex]\(y\)[/tex]-intercept: [tex]\(8\)[/tex]

Graphing the Equation

To graph the equation, plot the intercepts on the coordinate plane and draw the line that passes through these points.

1. Plot the point [tex]\((-10, 0)\)[/tex] on the x-axis.
2. Plot the point [tex]\((0, 8)\)[/tex] on the y-axis.
3. Draw a straight line through these two points, extending in both directions.

This line is the graph of the equation [tex]\(-\frac{x}{10} + \frac{y}{8} = 1\)[/tex]. Here's a rough sketch:

[tex]\[ \begin{array}{c} \begin{tikzpicture} \draw[thick, ->] (-11,0) -- (1,0) node[anchor=north west] {x}; \draw[thick, ->] (0,-1) -- (0,9) node[anchor=south east] {y}; \draw[thick,] (-10.0,0) node(pin north west left: $(-10,0)$) -- (0,8.0) node(pin north east left: $(0,8)$); \end{tikzpicture} \end{array} \][/tex]

With the points [tex]\((-10, 0)\)[/tex] and [tex]\((0, 8)\)[/tex], our line will intersect the axes at the correct intercepts as calculated.