Sure! Let's break it down step-by-step.
### Step 1: Initial Cross (PP x pp)
When a pea plant with genotype PP (purple flowers) mates with a plant with the genotype pp (white flowers):
- All possible offspring will have genotype Pp.
- As the dominant allele P codes for purple flowers, all offspring will have purple flowers.
Therefore, the possibility that the offspring will have purple flowers is:
[tex]\[1 \ (\text{100%})\][/tex]
### Step 2: Second Cross (Pp x pp)
Now, an offspring from the initial cross (Pp) mates with a plant having genotype pp:
- The Punnett square for this cross is as follows:
[tex]\[
\begin{array}{|c|c|c|}
\hline & P & p \\
\hline p & Pp & pp \\
\hline p & Pp & pp \\
\hline
\end{array}
\][/tex]
### Step 3: Analysis of Offspring Genotypes
Based on the Punnett square:
- There are two offspring with genotype Pp (purple flowers).
- There are two offspring with genotype pp (white flowers).
The probability that the offspring from Pp x pp cross will have purple flowers (Pp) is:
[tex]\[ \frac{2}{4} = 0.5 \ (\text{50%}) \][/tex]
### Step 4: Homozygous Dominant Probability
- From the same Punnett square, note that there are no possible homozygous dominant offspring (PP).
- Thus, the probability of having a homozygous dominant genotype (PP) is:
[tex]\[0 \ (\text{0%})\][/tex]
### Conclusion
Using the given question and correct descriptions above, we fill in the drop-down menus as follows:
1. The possibility that the offspring will have purple flowers is 0.5.
2. If an offspring from this cross mates with a pp, the possibility of homozygous dominant genotype for the flowers will be 0.
