Due on July 25th, 11:59pm

Exercise #1: Write each of the following expressions as the product of two binomials.

(a) [tex]4x(x-5) - 3(x-5)[/tex]
(b) [tex]12x^2 - 6x + 14x - 7[/tex]

Multiple Choice Question:

The factors of (a) are...

A. [tex](x-5)(4x+3)[/tex]
B. [tex](x+5)(4x-3)[/tex]
C. [tex](x-5)(4x-3)[/tex]



Answer :

Sure, let's solve the given question step-by-step in detail.

### Part (a): Factor the Expression [tex]\(4x(x-5) - 3(x-5)\)[/tex]

1. Given Expression: [tex]\(4x(x-5) - 3(x-5)\)[/tex]

2. Identify Common Factors:
Notice that [tex]\((x-5)\)[/tex] is a common factor in both terms of the expression.

[tex]\[ 4x(x-5) - 3(x-5) = (x-5)(4x) - 3(x-5) \][/tex]

3. Factor Out the Common Term:
Since [tex]\((x-5)\)[/tex] is a common factor, we can factor it out from both terms:

[tex]\[ (x-5)(4x) - (x-5)(3) = (x-5)(4x - 3) \][/tex]

4. Rewrite in Factored Form:
The expression can now be written as:

[tex]\[ 4x(x-5) - 3(x-5) = (x-5)(4x - 3) \][/tex]

From this detailed step-by-step solution, we find that the expression [tex]\(4x(x-5) - 3(x-5)\)[/tex] factors to [tex]\((x-5)(4x - 3)\)[/tex].

### Multiple Choice Answer for Part (a):

- [tex]\( (x-5)(4x+3) \)[/tex]
- [tex]\( (x+5)(4x-3) \)[/tex]
- [tex]\( (x-5)(4x-3) \)[/tex] ⟸ This is the correct answer.

### Part (b): Factor the Expression [tex]\(12x^2 - 6x + 14x - 7\)[/tex]

1. Given Expression: [tex]\(12x^2 - 6x + 14x - 7\)[/tex]

2. Combine Like Terms: First, combine the like terms:

[tex]\[ 12x^2 - 6x + 14x - 7 = 12x^2 + 8x - 7 \][/tex]

3. Factor by Grouping:
Let's use the method of factoring by grouping:

Group the terms to make it easier to factor:

[tex]\[ 12x^2 + 8x - 7 = (12x^2 + 8x) - 7 \][/tex]

4. Identify Common Factors in Grouped Terms:
Factor out the common factor from each group:

[tex]\(4x\)[/tex] is a common factor in the first group:

[tex]\[ 12x^2 + 8x = 4x(3x + 2) \][/tex]

Since [tex]\(-7\)[/tex] does not fit any obvious simplification, we factor the expression as:

[tex]\[ 4x(3x + 2) - 7 \][/tex]

Unfortunately, since there is no other term to group with [tex]\(-7\)[/tex], we cannot factor this expression any further simplification to binomials directly. Thus, [tex]\(12x^2 + 8x - 7\)[/tex] is already in its simplest form as the polynomial doesn't factor nicely into binomials using integers.

### Summary

So, the factors of [tex]\(4 x(x-5) - 3(x-5)\)[/tex] are [tex]\((x-5)(4x - 3)\)[/tex] which corresponds to option:

- [tex]\( (x-5)(4x-3) \)[/tex]

This concludes the step-by-step solution.