## Chapter Problems: Motion at Constant Speed

### Class Work

1. A rabbit can cover a distance of 80 m in 5 s. What is the speed of the rabbit?

2. During the first 50 s, a truck traveled at a constant speed of 25 m/s. Find the distance that it traveled.

3. An elevator ascends at a constant speed of 4 m/s. How much time is required for the elevator to travel 120 m upwards?

4. A racing car can complete a 900 m long lap in 15 s. What is the speed of the car?

5. It is known that a shark can travel at a speed of 15 m/s. How far can a shark go in 10 seconds?



Answer :

Let's go through each problem step-by-step:

### Problem 1:
A rabbit can cover a distance of 80 meters in 5 seconds. We need to find the speed of the rabbit.

We use the formula for speed:
[tex]\[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \][/tex]

Plugging in the values:
[tex]\[ \text{Speed} = \frac{80 \, \text{m}}{5 \, \text{s}} = 16 \, \text{m/s} \][/tex]

So, the speed of the rabbit is [tex]\( 16 \, \text{m/s} \)[/tex].

### Problem 2:
During the first 50 seconds, a truck traveled at a constant speed of 25 m/s. We need to find the distance it traveled.

We use the formula for distance:
[tex]\[ \text{Distance} = \text{Speed} \times \text{Time} \][/tex]

Plugging in the values:
[tex]\[ \text{Distance} = 25 \, \text{m/s} \times 50 \, \text{s} = 1250 \, \text{m} \][/tex]

So, the distance the truck traveled is [tex]\( 1250 \, \text{m} \)[/tex].

### Problem 3:
An elevator ascends at a constant speed of 4 m/s. We need to find how much time is required for the elevator to travel 120 meters upwards.

We use the formula for time:
[tex]\[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \][/tex]

Plugging in the values:
[tex]\[ \text{Time} = \frac{120 \, \text{m}}{4 \, \text{m/s}} = 30 \, \text{s} \][/tex]

So, the time required for the elevator to travel 120 meters is [tex]\( 30 \, \text{s} \)[/tex].

### Problem 4:
A racing car can complete a 900-meter-long lap in 15 seconds. We need to find the speed of the car.

We use the formula for speed:
[tex]\[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \][/tex]

Plugging in the values:
[tex]\[ \text{Speed} = \frac{900 \, \text{m}}{15 \, \text{s}} = 60 \, \text{m/s} \][/tex]

So, the speed of the car is [tex]\( 60 \, \text{m/s} \)[/tex].

### Problem 5:
It is known that a shark can travel at a speed of 15 m/s. We need to find how far the shark can go in 10 seconds.

We use the formula for distance:
[tex]\[ \text{Distance} = \text{Speed} \times \text{Time} \][/tex]

Plugging in the values:
[tex]\[ \text{Distance} = 15 \, \text{m/s} \times 10 \, \text{s} = 150 \, \text{m} \][/tex]

So, the shark can travel [tex]\( 150 \, \text{m} \)[/tex] in 10 seconds.

### Summary:
1. Speed of the rabbit: [tex]\( 16 \, \text{m/s} \)[/tex]
2. Distance the truck traveled: [tex]\( 1250 \, \text{m} \)[/tex]
3. Time required for the elevator: [tex]\( 30 \, \text{s} \)[/tex]
4. Speed of the racing car: [tex]\( 60 \, \text{m/s} \)[/tex]
5. Distance the shark can travel: [tex]\( 150 \, \text{m} \)[/tex]