What is the center of a circle represented by the equation [tex]$(x+9)^2+(y-6)^2=10^2$[/tex]?

A. [tex]$(-9,6)$[/tex]
B. [tex]$(-6,9)$[/tex]
C. [tex]$(6,-9)$[/tex]
D. [tex]$(9,-6)$[/tex]



Answer :

Let's analyze the given equation of the circle step by step to find its center.

The standard form of the equation of a circle is:

[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]

where [tex]\((h, k)\)[/tex] is the center of the circle and [tex]\(r\)[/tex] is the radius of the circle.

We are given the equation:

[tex]\[ (x + 9)^2 + (y - 6)^2 = 10^2 \][/tex]

Our goal is to rewrite this given equation in the standard form and identify the values of [tex]\(h\)[/tex] and [tex]\(k\)[/tex] which represent the coordinates of the center of the circle.

Notice that in the given equation, we have:

[tex]\[ (x + 9)^2 \][/tex]

This can be rewritten as:

[tex]\[ (x - (-9))^2 \][/tex]

indicating that [tex]\(h = -9\)[/tex].

Similarly, we have:

[tex]\[ (y - 6)^2 \][/tex]

which is already in the form [tex]\((y - k)^2\)[/tex] with [tex]\(k = 6\)[/tex].

Thus, by comparing the given equation [tex]\((x + 9)^2 + (y - 6)^2 = 10^2\)[/tex] with the standard form [tex]\((x - h)^2 + (y - k)^2 = r^2\)[/tex], we can see:

- The center [tex]\(h\)[/tex] is [tex]\(-9\)[/tex]
- The center [tex]\(k\)[/tex] is [tex]\(6\)[/tex]

Therefore, the coordinates of the center of the circle are [tex]\((-9, 6)\)[/tex].

Among the given options, the correct answer is:

[tex]\[ (-9, 6) \][/tex]